Set up simultaneous equations for the analysis of Mo, Ti and V mixture by the peroxide method, using the data below. Standard solutions of Mo, Ti and V each at a known concentration of 2.00 mg of metal in a volume of 50.00 mL were measured at three wavelengths. Absorbances were measured to be: Metal 330nm 410nm 460nm Mo 0.416 0.048 0.000 Ti 0.130 0.608 0.410 N 0.000 0.148 0.200 An unknown solution was treated and diluted to a volume of 50.00 mL and the following absorbances were obtained: Abs at 330 nm = 1.189 Abs at 410 nm = 1.405 Abs at 460 nm = 0.952 Determine the mass (in mg) of each metal present in the unknown solution. Enter your numerical answer into the space provided: mass Mo= mg mass Ti = mg mass V = mg

Appl Of Ms Excel In Analytical Chemistry
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Chapter12: Spectrochemical Methods
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Set up simultaneous equations for the analysis of Mo, Ti and V mixture by the peroxide method, using the data below.
Standard solutions of Mo, Ti and V each at a known concentration of 2.00 mg of metal in a volume of 50.00 mL were measured at three wavelengths.
Absorbances were measured to be:
Metal 330nm
410nm 460nm
Mo
0.416
0.048
0.000
Ti
0.130
0.608
0.410
N
0.000
0.148
0.200
An unknown solution was treated and diluted to a volume of 50.00 mL and the following absorbances were obtained:
Abs at 330 nm = 1.189
Abs at 410 nm = 1.405
Abs at 460 nm = 0.952
Determine the mass (in mg) of each metal present in the unknown solution.
Enter your numerical answer into the space provided:
mass Mo=
mg
mass Ti =
mg
mass V =
mg
Transcribed Image Text:Set up simultaneous equations for the analysis of Mo, Ti and V mixture by the peroxide method, using the data below. Standard solutions of Mo, Ti and V each at a known concentration of 2.00 mg of metal in a volume of 50.00 mL were measured at three wavelengths. Absorbances were measured to be: Metal 330nm 410nm 460nm Mo 0.416 0.048 0.000 Ti 0.130 0.608 0.410 N 0.000 0.148 0.200 An unknown solution was treated and diluted to a volume of 50.00 mL and the following absorbances were obtained: Abs at 330 nm = 1.189 Abs at 410 nm = 1.405 Abs at 460 nm = 0.952 Determine the mass (in mg) of each metal present in the unknown solution. Enter your numerical answer into the space provided: mass Mo= mg mass Ti = mg mass V = mg
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