Question 4 Student L was extracting trimyristin (structure shown below) from nutmeg using n- hexane. She uscd 20 mL hexane and 4.0 g of nutmeg and succeeded in retricving 2.0 g of trimyristin crude product. After purification and recrystallization step using 10 ml of dichloromethane, only 1.0 g of pure trimyristin were filtered out. Further drying lead to 0.8 g final product. What is the percent recovery rate of trimyristin from nutmeg based on the scenario provided above? ndefined

Macroscale and Microscale Organic Experiments
7th Edition
ISBN:9781305577190
Author:Kenneth L. Williamson, Katherine M. Masters
Publisher:Kenneth L. Williamson, Katherine M. Masters
Chapter43: Amines
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0.8g/20 mLx100%=4%
0.8g/4.0gx100%=20%
0.8g/10 mLx100% =8%
2.0g/4.0gx100%=50%
1.0g/20 mLx100% =5%
1.0g/4.0gx100%=25%
1.0g/10 mLx100%=10%
Transcribed Image Text:0.8g/20 mLx100%=4% 0.8g/4.0gx100%=20% 0.8g/10 mLx100% =8% 2.0g/4.0gx100%=50% 1.0g/20 mLx100% =5% 1.0g/4.0gx100%=25% 1.0g/10 mLx100%=10%
Question 4
Student L was extracting trimyristin (structure shown below) from nutmeg using n-
hexane. She used 20 mL hexane and 4.0 g of nutmeg and succeeded in retrieving 2.0
g of trimyristin crude product. After purification and recrystallization step using 10
ml of dichloromethane, only 1.0 g of pure trimyristin were filtered out. Further
drying lead to 0.8 g final product.
What is the percent recovery rate of trimyristin from nutmeg based on the scenario
provided above?
undefined
O 0.8g/20 mLx100%=4%
0.8g/4.0gx100%=20%
0.8g/10 mLx100% =8%
Transcribed Image Text:Question 4 Student L was extracting trimyristin (structure shown below) from nutmeg using n- hexane. She used 20 mL hexane and 4.0 g of nutmeg and succeeded in retrieving 2.0 g of trimyristin crude product. After purification and recrystallization step using 10 ml of dichloromethane, only 1.0 g of pure trimyristin were filtered out. Further drying lead to 0.8 g final product. What is the percent recovery rate of trimyristin from nutmeg based on the scenario provided above? undefined O 0.8g/20 mLx100%=4% 0.8g/4.0gx100%=20% 0.8g/10 mLx100% =8%
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