help to solve this Question 2Answer the following questions about a common emitter amplifier.Vee(a) Draw the circuit diagram of a common emitter amplifier using an n-p-n transistor. In+10V, R₁ = 20kn, R₂ = 3.6kn, R = 1.2K, R = 5000, R1000, RL 30kn, C=100μF, C=10μF, t = 10μF, v=0.01sinot, and Bthe circuit,100.=(b) Calculate the DC bias values and AC emitter resistance, re(c) Draw the Box Model and determine all the amplifier parameters including inputresistance R, output resistance Ro, and voltage gain A.(d) Let vs = 0.01 Vp (sine wave with a peak amplitude of 0.01 V). What is the AC peakvoltage seen at the load resistor, R₁?(e) If you want the circuit to produce a voltage gain A of -100, can you change the valueof Rg to achieve?

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Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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SIGNAL Mention the function or work of each component in the circuit? + Vcc Rc Rc Cc HH www R₁ Cin HH R₂ www. RE Cc HH CE www R₁ 30 www wwww RE CE OUTPUT
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C6 Shown in Figure C6 is a common emitter amplifier. Follow the specification below and calculate the value of R1 given the information provided. RC Voe vce Vbe vcc = 10 V, VE=1 v, VBE = 0.7 V, IC = 2 mA, B = 100, I(R1) = 10XIB, V(RC) = VCE = 4.5 v RI RL Ve Vbb Figure C6 Common Emitter amplifier with Potentiometer Bias A. No answers below are correct B. R1 = 13.5 ko C. R1 = 21.6 kO D. R1 = 8.5 kn
3. For the following circuit assumer, = 33.4 N a. Draw the small signal equivalent circuit. b. Find the input impedance. c. Find output impedance. d. Find the voltage gain. -10 V 68 k2 4.7 kA e. Find the current gain. a = 0.998 10 uS
What output voltage results in the circuit below for an input of 0.5 V. Refer to the following for the values of Rf = 413981 ohms, R1 = 16788 ohms. Express your answer up to two decimal places. ... V. 360 kQ 12 ko Round your answer to 2 decimal places.
You are working as a hardware engineer in an R&D department and your new task is to design a voltage divider bias circuit. Vcc You are told that you have to use a 2N2222A transistor manufactured by Central Semiconductor Corp. and a power supply of Vcc = 22 V. RC R1 a. Find the datasheet of the selected transistor in Internet and upload it together with your homework. b. From the datasheet identify the range of B suitable for the Ica required in this problem and use the minimum value in your design. R2 RE c. Calculate the values of four resistors so that VCEQ = 12V and Ica = 1.4 ma. Make sure that you select standard resistor values. d. Plot the load line and indicate the operating point on it. Is the location of operating point is a good one for an amplifier with a reasonable performance ? Explain your answer.
Choose the correct answer 1. Common emitter configuration of BJT is a a) Current Amplifier b) Voltage Amplifier c) Both a and b d) None of the above 2. Common base configuration of BJT is a a) Current Amplifier b) Voltage Amplifier c) Both a and b d) None of the above 3. Function generators and AC source in Multisim are a) Similar in nature b) Function generators can generate more waveforms while AC source is a square wave c) AC source is just a 220V, 50Hz wave d) Function generate can generate more waveforms while AC source is a asine wave 4. Common collector configuration of BJT is a a) Current Amplifier b) Voltage Amplifier c) Both a and b d) None of the above 5. How can you control the output voltage of a common emitter amplifier BJT a) By RB b) By RE c) By VCC d) By coupling capacitor
iv) dc collector to emitter base voltage, VEca v) dc base voltage, VB vi) dc collector voltage, Vc vii) dc emitter voltage, VE and viii) dc base collector voltage, Vsc. ix) ac and dc loadline by using appropriate sketches x) maximum output swing, Vo max. Given : VEB = 0.7V and ß = 100. 12 V 82k 3k3 C. o Vo Vi o H 1k0 39k CE Figure Q3b
Assume VRE 0.7 V and B-50 for the transistor in the circuit shown in the figure. For VCE = 2 V, the value of Rg is RB m B +12 V www Rc- 5 k C E VCE
(CLO-3, C3, C5 , C4)a. Draw a Thevenin equivalent circuit of the circuit shown in the figure below b. Drive the equation for emitter current IEc. Find the collector current Ic and VEC ?R1 = (010 + 25) kΩ R2 =15kΩRC = 3 kΩRE = 1.4 kΩβDC = 150 VEE = +12 V
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We examined the common source amplifier shown in the figure in the 5th experiment. The selection criterion of the input capacitance is Xcin = 0.1Rin: Calculate the required input capacitance value, Cin , if an input signal with a frequency of 2 kHz is applied. Şekitde gösterilen ortak source yükseltecini 5. deneyde incelemiştik Giriş kapasitesinin seçim kriteri Xcin - 0.1Rin dir. 2 kHzlik giriç sinyali için gerektt tapasite, Cm değerini hesaplayınız. Circuit parameters / Devre Parametreleri R1 = 53 k2, R, = 17 k2 R1 RD Cout Vout D VDD M2 Cin G Vin R2 RS cs O a. 74.19 nF O b. 86.55 nF O c. 49.46 nF O d. 61.82 nF O e. 43.28 nF

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