Question 1This is the situation of the leftmost image. (Theparticles move vertically, up and down.)• M = 8 kg• m = 2 kg• V = 5 m/s ĵ• v = -20 m/s ĵYou might verify on your own that the totalmomentum is zero.Calculate the total kinetic energy of the system (inJoules). CoM is stationary.mÎM

Answered: Image /qna-images/answer/75f6f070-7aa5-4a38-b509-c7cfe05fe49c.jpg

Question 1 This is the situation of the leftmost image. (The particles move vertically, up and down.) • M = 8 kg •m = 2 kg • V = 5 m/s ĵ • v = -20 m/s ĵ %3D %3D You might verify on your own that the total momentum is zero. Calculate the total kinetic energy of the system (in Joules).

Question 1 This is the situation of the leftmost image. (The particles move vertically, up and down.) • M = 8 kg •m = 2 kg • V = 5 m/s ĵ • v = -20 m/s ĵ %3D %3D You might verify on your own that the total momentum is zero. Calculate the total kinetic energy of the system (in Joules).

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 70P

See similar textbooks

Similar questions

I need to find the angle of projection for the maximum range. I have the following information: angle (degrees) and average range (cm). Here are two angles and the range for each. Angle Average Range (cm) 10 146.5 45 272.5 I think that I use this formula but I am not for sure. R=(V20 sin 2 theta)/g Can you help me figure this out so that I can do the rest of the angles and ranges.
Abel is not sure why, from h = Yi Sih- 0, the height the tennis ball reaches is maximum when 0, = 90°, and 2g asks Kato to explain. Which of Kato's responses is correct? O "When 0, = 90°, sin? 0, = sin(20,) = 1, which is its maximum value, so h is maximum." "When 0, = 90°, sin? 0, is maximum, so h is maximum." "When 0, = 90°, sin? 0, is minimum, so h is maximum." "When 0, = 90°, sin 0, = 1, sin? 0, = 2.1 = 2, which is its maximum value, so that means h is maximum."
You need to guide a robot from the red dot on the left to the green dot on the right, avoiding the blue walls along the way. units To do this, you must feed it a series of commands of the form "turn degrees and move forward". Angles are measured in degrees, with positive angles turning counterclockwise, and negative angles turning clockwise. All turns are relative to the robot's current direction. The grid marks 1 unit squares. From the red starting dot, with the robot facing directly to the right, issue your commands: (all commands should be given as decimal values) Move 1: Turn 9 Move 2: Turn Move 3: Turn Move 4: Turn degrees and move degrees and move degrees and move degrees and move units forward units forward units forward units forward
A laser pointer is placed on a platform that rotates at a rate of 19 revolutions per minute. The beam hits a wall 8 m away, producing a dot of light that moves horizontally along the wall. Let 0 be the angle between the beam and the line through the searchlight perpendicular to the wall. How fast is this dot moving when 0 = Wall π ? 6 8 m Laser (Use decimal notation. Give your answer to one decimal place.) velocity of the dot: m/min
y-India's largest lear X ! Unacademy - India's largest + A unacademy.com/educator/doubts/solve?topic3DVKKVN need help with this question A neutron beam of initial kinetic energy E, is divided into two beams at point O by some mechanism. Thereafter the beams proceed on the path OẶC and OBC without a phase change at the corners A and B to interfere with each other at point C. Here OACB is a square of side I, tilted at an angle 0 above the horizontal. Mass of the neutron is m, Planck's constant is h and acceleration of free fall is g. the possible expression(s) for angle 0 at which a Maxima is detected at C is/are B Horizontal A 2hl /2mE, -h² 2m gl³ 2hl/2mE, 2h (A) sin (B) sin- m'gl m°gl 6hl /2mE, -9h² 2m gl 2hl/2mE, -h² 2m gl (C) sin (D) tan e Acivate Go to Settin 6 29°C Partly cloudy P Type here to search Home End F10 SC FD F2 & %23 2$ 4 7 7 8. W R 5 10
Please solve parts d, e, f, g. Answers for a-c: a) E=Q/(4πε0r2) for r<a b) E=Q/(4πε0r2) for a<r<b c) E=1/(4πε0r2)(-Q/3r2) for b<r<c
What is wrong with the following expressions? How can you correct them? (a) C=AB , (b) C=AB , (c) C=AB , (d) C=AB , (e) C+2A=B , (f) C=AB , (g) AB=AB , (h) C=2AB , (i) C=A/B , and (j) C=A/B .
Kindly give me a detailed answer in a clear handwriting of subpart (c). I am attaching the full question but I only need (c). All the questions are related. I only have few minutes kindly give the ans ASAP. I will upvote if the answer is correct and answered soon. Thank you.
Kindly give me a detailed answer in a clear handwriting of subpart (b). I am attaching the full question but I only need (b). All the questions are related. I only have few minutes kindly give the ans ASAP. I will upvote if the answer is correct and answered soon. Thank you. ( It's my 2nd time asking it. It is the whole question no part is missing)
b) In your own words describe first moment of area for any shape and its importance. With reference to the shape below about the axis s - s, describe the position of the centroid. 40 mm 10 mm A 10 mm 60 mm 10 mm 30 mm
Suppose i = 31 + 8j – 18k and u = 3i + 3j + k. Compute the following: %3D The cosine of the angle between v and u is The scalar component of u in the direction of v is proj, i =
Phys1401-Spr20 HW2 Vectors, x G how to screensho ton macbook X webassign.net/web/Student/Assignment-Responses/submit?dep=23311825&tags=autosave M Apps Twitter N Netflix Spotify YouTube Мaps Gmail P MyLabsPlus | Pear... Bb Welcome, Lizzette.. Mail - Hernandez,... SA [SP-20] PHYS-14... First-Year Learnin... velocity equation can be used to find v. LEARN MORE REMARKS From the figure, we see that this problem can be solved with the Pythagorean theorem, Because the problem involves a right triangle: the boat's x-component of velocity exactly cancels the river's velocity. When this is not the case, a more general technique is necessary, as shown in the following exercise. Notice that in the x-component of the relative velocity equation a minus sign had to be included in the term -(10.0 km/h)sin 0 because the x-component of the boat's velocity with respect to the river is negative. QUESTION If the boat is instead heading due north relative to the water (instead of relative to the shore) while…