Q4/Full the following blanks(1101 1010)BCD(5211) = ()BCD(3321)=()EX-3=()16 *(1101 1010)BCD(5211) = (11101100)BCD(3321)=(1010110)EX-3=(A6)16(1101 1010)BCD(5211) = (11100111)BCD(3321)=(1011001)EX-3=(56)16(1101 1010)BCD(5211) = (11010111)BCD(3321)=(1011001)EX-3=(2B)16(1101 1010)BCD(5211) = (10111110)BCD(3321)=(1000111)EX-3=(44)16%3DNone of them

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Answered: Q4/Full the following blanks (1101…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Q4/ The decimal 793.251)= ( number number ( O 1431.204 O 1431.200 O No one of them O 1341.200 O 1341.201 ) in octal
Full the following blanks (1101 1010)BCD (5211) = ( )BCD(3321)=( EX-3=( )16 O (1101 1010)BCD (5211) = (1110 0111)BCD(3321)=(1011001)EX-3=(56)16 O (1101 1010)BCD (5211) = (1110 1100) BCD (3321)=(1010110) EX-3=(A6)16 O (1101 1010)BCD (5211) = (1011 1110)BCD(3321)=(1000111)EX-3=(44)16 None of them O (1101 1010)BCD (5211) = (1101 0111) BCD(3321)=(1011001)EX-3=(2B)16
What will be the final value of DI after executing the following piece of code? Execute the instructions dependently one after another. CLD MOU CX,OFOH MOU AX,05678H MOU DI,01000H MOU ES, DI SUB DI, DI REPNZ SCASB -R AX-0000 DS-073F 073F:0100 0000 D 1000:0 F 1000:0000 92 00 14 12 54 56 44 78-AD 56 78 FO 00 00 00 00 BX-0000 CX-0000 DX-0000 SP-00FD ES-1000 SS%3073F CS=073F BP-0000 SI=0000 DI=0000 IP-0100 NU UP EI PL NZ NA PO NC ADD IBX SI1,AL DS:0000 CD TUDX.Ux..... .... Notes: 1- Use the DEBUG window to answer this question (values shown are prior to execution and in hexadecimal 2- Write down the final value of DI as four hexadecimal digits without any additional characters.
Design an encoding matrix with diodes and resistors to display a decimal number to on the seven-segment display. You have 10 switches (WO-W9) with one terminal connected to Vec. For decimal number 0, switch 0 (S0) is closed, for decimal number 1, switch 1 (S1) is closed etc. (Switches are on the vertical axis, S0 on top and the outputs are taken on the horizontal axis (Y0-Y6), with “a" on the left and "g" on the right. Note that (Y0-Y6) outputs are used as inputs to seven-segment display. Since these outputs cannot drive the seven segment display LEDS you may need additional bipolar transistors and resistors. The supply voltage is 5V and each LED needs a current of 20mA. Note that this is a design problem and the design is not unique. Do your best! f a a e
Q4/ The decimal 793.251)= ( number O 1431.200 O No one of them 1431.204 number ( O 1341.200 O 1341.201 ) in octal
What output does the following multiplexer output? Note: if a line is cut and a number is written, it shows how many bits or how many lines are there. The lines below are 4 bits.
Q1/ Design Carry Look a head adder that add two (1-digit) BCD numbers.
USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…
(c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).
5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101
Given A = 40 and B = 60 in base 10. %3D %3D convert A and B to binary using 7 digits find – B in binary using 2's complement Find S = A+ (-B)in binary, Convert the result using 2' scomplement method to find the S in decimal representation. (you should get – 20).
Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W XY Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C

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