Q1\ Determine the ratio of the force exerted by the sun on the moon to that exerted by theearth on the moon for position A of the moon. Repeat for moon position B. where Me5.976(1024) kg, Mm 7.347 x 1022 Kg. M, 1.99(1030) Kg. The distance between moonand the earth =384.398(10)m and distance between earth and the sun == 150(10) m.G-6.673(10¹)m³/kg.s²SunlightADB

Answered: Image /qna-images/answer/4f235ca3-c3af-4bb5-877e-9379edb26b84.jpg

Q1\ Determine the ratio of the force exerted by the sun on the moon to that exerted by the earth on the moon for position A of the moon. Repeat for moon position B. where M 5.976(1024) kg, Mm 7.347 x 1022 Kg. M, 1.99(1030) Kg. The distance between moon and the earth =384.398(106)m and distance between earth and the sun = 150(10) m. G-6.673(10¹)m³/kg.s² Sunlight AO B

Q1\ Determine the ratio of the force exerted by the sun on the moon to that exerted by the earth on the moon for position A of the moon. Repeat for moon position B. where M 5.976(1024) kg, Mm 7.347 x 1022 Kg. M, 1.99(1030) Kg. The distance between moon and the earth =384.398(106)m and distance between earth and the sun = 150(10) m. G-6.673(10¹)m³/kg.s² Sunlight AO B

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Mountain pull. A large mountain can slightly affect the direction of “down” as determined by a plumb line. Assume that we can model a mountain as a sphere of radius R=2.00 km and density (mass per unit volume) 2.6*103 kg/m3. Assume also that we hang a 0.50 m plumb line at a distance of 3R from the sphere’s center and such that the sphere pulls horizontally on the lower end. How far would the lower end move toward the sphere?
Take P = 660 lb. (Figure 1) Figure y E 4 ft X P -2 ft- D T 2 ft 1 ft 3 ft 1 of 1 > Part A Determine the horizontal and vertical components of force that the pin at B exert on member ABD of the frame. Express your answer in pounds to three significant figures. Enter your answer separated by a comma. = B₁. By 1320,- 660 Submit Part B VA£¢ ΑΣΦ Dz. Dy = X Incorrect; Try Again; 4 attempts remaining Term 1: Check your signs. Submit Provide Feedback vec Previous Answers Request Answer 6 Determine the horizontal and vertical components of force that the pin at D exert on member ABD of the frame. Express your answer in pounds to three significant figures. Enter your answer separated by a comma. IV—| ΑΣΦ VE Request Answer ↓↑ vec 4 ? B lb ? lb
Assume that all quantities are good to 3 significant figures...do not start rounding off too early or too much! All numeric answers should be entered rounded to 3 significant figures and assuming proper SI Units unless otherwise stated. Consider just these 2 forces acting on a mass of 2.79 kg. F1 = 8.36 N @ 21.5 degrees and F2 = 6.80 N @ 76.7 degrees where the angles are measured relative to the +x direction. What is the magnitude of the acceleration produced considering only these 2 forces acting?
There are two forces on the 2 kg box in the overhead view of the figure, but only one is shown. For F1 20N, a = 12m/s² and 0 = 30°. A) Find the second force in unit-vector notation B) Find the angle between the second force and the x- axis.
5N force is applied to the object. What will be the y-component of the same applied force if the x-component of the force is 3N?
Two forces act on a 2.55 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced (4.05î – 3.30j) m. Write th second force in unit vector notation. (Enter your answer in kg • m/s?. Assume the gravitational force acts in the -j direction.)
At what angle must the 530-lb force be applied in order that the resultant R of the two forces have a magnitude of 1060 lb? For this condition what will be the angle 3 between R and the horizontal? 530 lb 790 lb Answers: 0 = i B = i O
At what angle & must the 520-lb force be applied in order that the resultant R of the two forces have a magnitude of 1100 lb? For this condition what will be the angle /ß between R and the horizontal? 520 lb 770 lb Answers: i B- i
Two forces act on a 4.15-kg object: 31.1 N in the +x direction and 68.5 N in the -y direction. What is the amount of the object's acceleration (in m/s )? [3 sig. figs.] Answer. -9.01 What is the direction of the object's acceleration (in degrees counterclockwise from +x) [3 sig. figs.] Answer. 75.2
A stone weighing 10 Newtons is sitting on the side of a hill that is at a 30o angle with the horizontal. What is the magnitude of the component of the stone's weight parallel to the side of the hill.
A 284N crate resting on a plane inclined 37-degrees with the horizontal requires a 23.9N force to bring it down to 6.4m from its initial position. The force is applied 55-degrees with respect to the horizontal. Neglecting friction between the crate and plane, determine the time (in seconds) that the crate had travelled a distance of 6.4m. Answer in two decimal places. Numerical values only. Don't indicate units here, just on the submitted solution.
a bridge across a small stream is made by supporting a 10m long log with a mass of 75kg with ropes tied at the ends of the log to the tree on the banks. the rope on the right makes a 25 degree angle with the ground. the rope on the left makes a 20 degree angle with the ground. a 25kg child us standing 7.5 m from the left bank. write the net force equation for the y direction. write the net force equation for the x direction. write the torque equation (use the left end of the log as the axis of rotation).