Punnett Square problem. In fruit flies, eye color is a sex-linked trait. A female fruit fly with white eyes mates with a male fruit fly with red eyes. What are the genotypic and phenotypic ratios of the offspring? Show your work for full credit.
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- Genetics Problems. Show your crosses. It must contain: (a) parental genes, (b) genotypic ratio, (c) phenotypic ratio, (d) hybrid cross and (e) other answer needed in the question. A. Cock-feathering in chickens is a trait limited to expression only in males and is determined by the autosomal recessive genotype hh. The dominant allele H produces henfeathered males. All females are hen-feathered regardless of genotype. A cock-feathered male is mated to a female. Show the cross.INCOMPLETE DOMINANCE. All of the traits in these problems show incomplete dominance. Work these as you did the other monohybrid crosses, but interpret your results with the rules for incomplete dominance. 1. In snapdragons, flower color shows incomplete dominance. Red color is dominant to write color. What kind of offspring could result from Parent 1 being heterozygous and Parent 2 have a white flower color? Trait:Neep help ASAP. A red flowered plant was crossed with a blue flowered plant and produced all purple flowered plants. When the purple flowered plants were crossed with each other they produced 5 red plants, 5 blue plants, 20 deep purple plants, 20 light lilac plants, and 30 purple plants How many genes are involved in the color production? Assume that red color is caused by an A allele and blue color by a B allele and determine the likely genotype of the plants in the F2 generation.
- Genetics Problems. Show your crosses. It must contain: (a) parental genes, (b) genotypic ratio, (c) phenotypic ratio, (d) hybrid cross and (e) other answer needed in the question. A. Let us consider two sex-influenced traits simultaneously, pattern baldness and short index finger, both of which are dominant in men and recessive in women. A heterozygous bald man with long index finger marries a heterozygous long-fingered, bald woman. Determine the phenotypic expectations for their children.ess in males. A male i1s either normal or has colorblindness. He cannot be a carrier. The allele for colorblindness is carried on the X chromosome and is recessive. A man, whose father was colorblind, has a colorblind daughter. a) Is this man colorblind? How do you know? b) Where did he get his gene for colorblindness? c) Must the fathers of all colorblind girls be colorblind? Why? 1. A man whose parents were normal with respect for color vision marries a woman of normal vision and similar pedigree. One of their daughters is colorblind. Give the genotypes of this daughter, her parents, and paternal grandparents. Is the girl's father colorblind? 2. 100% Give Feedba 10 >>Incomplete dominance. A dog with a black coat mates with a dog with a white coat, and all of the offspring have gray coats, a result due to incomplete dominance. What must the genotypes of the parents and the offspring be, assuming that CB = black coat and CW = white coat? please show punnet square also
- Genetics Problems. Show your crosses. It must contain: (a) parental genes, (b) genotypic ratio, (c) phenotypic ratio, (d) hybrid cross and (e) other answer needed in the question. An albino is a person with no pigmentation in his skin, eyes or hair. Normal pigmentation is (A) is dominant over albino (a). A normal pigmented man marries a homozygous normal woman. What would the expected appearances of the children beselves in the offspring. The crosses are lled ssed differently in homozy- heterozygous individuals. This produces a con- dition called incomplete dominance. In such cases, both worked out in the same manner as indicated previously, but heterozygous offspring exhibit a phenotype interme- diate between that of the homozygous individuals. Some examples follow. Activity 2 Working Out Crosses Involving Incomplete Dominance 1. The inheritance of flower color in snapdragons illustrates the principle of incomplete dominance. The geno-type RR is expressed as a red flower, Rr yields pink flowers, and rr produces white flowers. Work out the following crosses to determine the expected phenotypes and both genotypic and phenotypic percentages. % of each phenotype: 2. In humans, the inheritance of sickle cell anemia/trait is deter- mined by a single pair of alleles that exhibit incomplete domi- nance. Individuals homozygous for the sickling gene (s) have sickle cell anemia. In double dose (ss), the…Two Manx cats mate. Manx allele is dominant but is lethal in homozygous individuals. What is the probability that the first three offspring will display the wild-type phenotype (non-Manx)? Show your work including a Punnett square.
- Deletion mapping: In your diploid model organism, one copy of the chromosome has all normal, dominant alleles of these genes. It is P Q R STU V (not necessarily in that order). But the other copy of the chromosome has all recessive alleles, p q r stu v. You find various deletions in which chunks of the "dominant chromosome" are missing, and so there are recessive phenotypes as shown: Phenotype -- recessive for genes... T, Q, and U R, V, and S T and U S and V Q, P, and R R and S First deletion Second deletion Third deletion Fourth deletion Fifth deletion Sixth deletion Seventh deletion T and Q Figure out the order of the genes. Show some kind of work.olving Monohybrid Inheritance single gene. crosses. The henotypic traits controlled by a single gene. The problems are to give you practice in problem solving using Mendelian genetics. A dominant gene (W) produces wire-haired texture in dogs; its recessive allele (w) produces smooth hair. A group of heterozygous wire-haired individuals are crossed and their F1 progeny are then test-crossed. Determine the expected genotyplc and phenotypic ratios among the test cross progeny:Dominant Traits. A couple is going to have a baby. They are concerned about Huntington's Diseases, which results from having a dominant copy of the Huntington allele ("H"). Homozygous recessive individuals ("hh") are not affected. Thus, having one dominant version of the gene results in an affected phenotype. The woman is not affected, but the man is. What alleles does mom have? What alleles does that have? Make a punnett square