Use line notation to represent each electrochemical cell below a.  2Ag+(aq)+Pb(s)→2 Ag(s)+Pb2+(aq) b.  2ClO2(g)+2 I−(aq)→2 ClO2−(aq)+I2(s) c.  O2(g)+4 H+(aq)+2 Zn(s)→2 H2O(l)+2 Zn2+(aq)

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Chapter18: Electrochemistry
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Problem 151CP: Consider the following galvanic cell: Calculate the concentrations of Ag+(aq) and Ni2+(aq) once the...
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Use line notation to represent each electrochemical cell below

a.  2Ag+(aq)+Pb(s)→2 Ag(s)+Pb2+(aq)

b.  2ClO2(g)+2 I−(aq)→2 ClO2−(aq)+I2(s)

c.  O2(g)+4 H+(aq)+2 Zn(s)→2 H2O(l)+2 Zn2+(aq)

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Pb is getting oxidized to Pb2+, so in part A it is Pb | Pb2+ . But then why in part b, even thought I- is getting oxidized to I2, the cell representation is:   I2 | I-    , and why is Pt added to the end? Also in part c, why isnt O2 after H+, if O2 is the first one in the equation getting reduced ?

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can you explain the cell represention for each part? Like why is it that way

 

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