Part E What is the cell potential for the reaction at 57 °C when [Fe2+] = 2.90 Mand [Mg2+] = 0.210 M. Express your answer to three significant figures and include the appropriate units. ►View Available Hint(s) E = μA Value Units Mg(s)+Fe2+ (aq)→Mg2+ (aq) + Fe(s) ?

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Chapter18: Electrochemistry
Section: Chapter Questions
Problem 5RQ: The Nernst equation allows determination of the cell potential for a galvanic cell at nonstandard...
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+ Introduction to the Nernst Equation
Learning Goal:
To learn how to use the Nernst equation.
The standard reduction potentials listed in any reference table are only
valid at the common reference temperature of 25 °C and standard
conditions of 1 M for solutions and 1 atm for gases. To calculate the
cell potential at nonstandard conditions, one uses the Nernst equation,
2.303 RT
E = E
nF
-log10 Q
where E is the potential in volts, E is the standard potential at 25 °C
in volts, R = 8.314 J/(K-mol) is the gas constant, T is the
temperature in kelvins, n is the number of moles of electrons
transferred, F = 96, 500 C/(mol e) is the Faraday constant, and
Qis the reaction quotient.
At the common reference temperture of 298 K, substituting each
constant into the equation the result is
E = E°
0.0592 V
n
log10
Q
Transcribed Image Text:+ Introduction to the Nernst Equation Learning Goal: To learn how to use the Nernst equation. The standard reduction potentials listed in any reference table are only valid at the common reference temperature of 25 °C and standard conditions of 1 M for solutions and 1 atm for gases. To calculate the cell potential at nonstandard conditions, one uses the Nernst equation, 2.303 RT E = E nF -log10 Q where E is the potential in volts, E is the standard potential at 25 °C in volts, R = 8.314 J/(K-mol) is the gas constant, T is the temperature in kelvins, n is the number of moles of electrons transferred, F = 96, 500 C/(mol e) is the Faraday constant, and Qis the reaction quotient. At the common reference temperture of 298 K, substituting each constant into the equation the result is E = E° 0.0592 V n log10 Q
▼
Was either rounded differently or used a different number of significant figure
Although the reaction given in the introduction is at an elevated temperature, the standard cell potential at 25 °C is used in
potential under non-standard conditions.
Part E
What is the cell potential for the reaction
E =
at 57 °C when [Fe²+] =
= 2.90 M and [Mg2+] =
= 0.210 M
Express your answer to three significant figures and include the appropriate units.
►View Available Hint(s)
Submit
μÅ
Value
Provide Feedback
Units
Mg(s) + Fe2+ (aq)→Mg2+ (aq) + Fe(s)
?
Transcribed Image Text:▼ Was either rounded differently or used a different number of significant figure Although the reaction given in the introduction is at an elevated temperature, the standard cell potential at 25 °C is used in potential under non-standard conditions. Part E What is the cell potential for the reaction E = at 57 °C when [Fe²+] = = 2.90 M and [Mg2+] = = 0.210 M Express your answer to three significant figures and include the appropriate units. ►View Available Hint(s) Submit μÅ Value Provide Feedback Units Mg(s) + Fe2+ (aq)→Mg2+ (aq) + Fe(s) ?
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