52%Part 9: Titrarion CalculationsBalnce the cquation Substitute into the formula with units Show your answer with unitsUse the following formula:M.VACAC.Ma and Ms:Molarity of the acid/baseV. and Vs:C. and Cs:Volume of the acid/baseCoefficient of the acid/base from the balanced equation.1 Ifit takes 25.0mL of HCI to neutralize 50.0 ml.of 3.0M NaOH, what is the molarity of the acid?HCI +NAOHNaC HO2 Irt takes 25.0mL of H-S to neutralize 50.0mL of 3.0M NAOH, what is the molarity of the acid?HS +NaOHNas +->3. If you start with 75.0mL of Ca{OH); and titrate it with 125mlL of 1.5M hydrobromic acid, what is themolarity of the base?HBrCafOH)CaBr+HO4. Given 80.0mL of 0.50M sulffuric acid, what volume of 0.75M potassium hydroxide is needed toneutralize the acid?_H;SO +KOHKSO +HO 52%S. Given 80.0ml. of 0.50M nitric acid, what volume of 0.75M lithium hydroxide is needed to neutralize theacid?HNO +LIOH--LINOHO6. If you titrate with 0.0075M phosphoric acid, what volume of this acid is needed to neutralize 2%5ml of0.025M magnesium hydroxide?Mg (PO) JLOKHOỂN1. l you react 25.7ml, of 0.05SOM HCIwith 38 Oml ef NaOH cakulate the molarity of le baseHCIIl vou react 255 Tal of 0.055UM H SO, Wih 38.0ml of N:OH cakulte the nolarty ef the baseSO.NaOHNa:SO,9. If you react 25 7m1 of 0 0550M IIC| wth 3x hnl of CarOfh, cakutate the molarity of the base.- DH10. If you react 25 7mL of0055OM H PO, Wih 38.0mL of Me(OH). cakulate the molrdvof the base.

Answered: Image /qna-images/answer/5b6f5a1d-3a84-47ce-896d-b9e143d38df4.jpg

Part 9: Balance the equation Substitute into the formula with units. Show your answer with units Use the following formula: M.VA = * MVa CA MA and Ms: Molarity of the acid/base V. and Vg: Volume of the acid/base C. and CB: Coefficient of the acid/base from the balanced equation. 1. Ift takes 25.0mL of HCI to neutralize 50.0 mt.of 3.OM NAOH, what is the molarity of the acid? HCI + NAOH NaCl+ HO 2 irit takes 25.0mL of H,S to neutralize 50.0mL of 3.0M NAOH, what is the molarity of the acid? HS + NaOH Na,S + 3. If you start with 75.0ml of Ca(OH); and titrate it with 125mL of 1.5M hydrobromic acid, what is the molarity of the base? HBr + Ca(OH)E CaBr+ H:O

Part 9: Balance the equation Substitute into the formula with units. Show your answer with units Use the following formula: M.VA = * MVa CA MA and Ms: Molarity of the acid/base V. and Vg: Volume of the acid/base C. and CB: Coefficient of the acid/base from the balanced equation. 1. Ift takes 25.0mL of HCI to neutralize 50.0 mt.of 3.OM NAOH, what is the molarity of the acid? HCI + NAOH NaCl+ HO 2 irit takes 25.0mL of H,S to neutralize 50.0mL of 3.0M NAOH, what is the molarity of the acid? HS + NaOH Na,S + 3. If you start with 75.0ml of Ca(OH); and titrate it with 125mL of 1.5M hydrobromic acid, what is the molarity of the base? HBr + Ca(OH)E CaBr+ H:O

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter16: Solutions

Section: Chapter Questions

Problem 100E: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a...

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Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a primary standard. It has the formula KHC8H4O4. This is often written in the short-hand notation as KHP. If 25.0mL of a potassium hydroxide solution are needed to neutralize 2.26g of KHP, what is the molarity of the potassium hydroxide solution? Potassium hydrogen phthalate sometimes called potassium biphthalate, as shown on this bottle is an acid that is convenient to store and use because it is a solid.
A bottle of concentrated hydroiodic acid is 57% HI by weight and has a density of 1.70 g/mL. A solution of this strong and corrosive acid is made by adding exactly 10.0 mL to some water and diluting to 250.0 mL. If the information on the label is correct, what volume of 0.988 M NaOH is needed to neutralize the HI solution? Suggest an indicator for the titration.
Explain why the hydrolysis of salts makes it necessary to have available in a laboratory more than one acid-base indicator for use in titrations.
Explain why an acid-base indicator changes color over a range of pH values rather than at a specific pH.
A solution is made by dissolving 15.0 g sodium hydroxide in approximately 450 mL water. The solution becomes quite warm, but after it is allowed to return to room temperature, water is added to bring the volume to 500.0 mL of solution. (a) Calculate the pH and pOH in the final solution. (b) Why would we wait for it to return to room temperature? (c) If the mass of the water used to initially dissolve the sodium hydroxide were exactly 450 g and the temperature of the water increased by 8.865 C, how much heat was given off by the dissolution of 15.0 g of solute? Assume the specific heat of the solution is 4.184 J/g. K. What is the molar heat change for the dissolution of sodium hydroxide (known as the enthalpy of solution, Hsol)?
A diprotic acid, H2B(MM=126g/moL), is determined to be a hydrate, H2B xH2O. A 10.00-g sample of this hydrate is dissolved in enough water to make 150.0 mL of solution. Twenty-five milliliters of this solution requires 48.5 mL of 0.425 M NaOH to reach the equivalence point. What is x?
. How is the strength of an acid related to the fact that a competition for protons exists in aqueous solution between water molecules and the anion of the acid?
A weak acid, HA, is dissolved in water. Which one of the following beakers represents the resulting solution? (Water molecules have been omitted for clarity.)
Which of the following is more likely to precipitate the hydroxide ion? Cu ( OH ) 2 ( s ) Cu 2+ ( aq )+ 2OH ( aq )K=1.6 10 19 Ca ( OH ) 2 ( s ) Ca 2+ ( aq )+ 2OH ( aq )K=7.9 10 6
There is a buffer system in blood H2PO4 HPO42 that helps keep the blood pH at 7.40. (K aH2PO4 =6.2108). (a) Calculate the[ H2PO4 ]/[ HPO42 ] ratio at the normal pH of blood. (b) What percentage of the HPO42 ions are converted to H2PO4 when the pH is 7.00? (c) What percentage of the H2PO4ions are converted to HPO42 when the pH is 8.00?