numbers. Perform the following computations on the given unsigned binary a) 101010101101 b) 1110100-0101110 c) 10110 10010 * (Note: give the full 9-bit result)
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- a) Convert the decimal number - 222 into a signed binary number using (1) sign-magnitude method (2) 1's complement method (3) 2's complement method b) If the above decimal number is positive , that is + 222, then convert it to a signed binary number using 1 's complement method c) Do the following binary subtraction: 110100101.10111- 000001100.11010b) There are five binary or hexadecimal numbers and six decimal conversions. Draw a line to connect each binary/hexadecimal to decimal number. Binary/Hexadecimal Decimal 4E 78 11011010 157 10011101 167 A7 25 19 218Q2: Answer three of the following branches: 1. Add (01110101)2 with (00110011)2 in Decimal, Binary Octal and Hexadecimal. 2. Find (5.5)10) ^3 in binary multiplication. 3. Divide (30.25)10 by (5.5)10 in binary division. 4. Subtract (00110011): from (01110101): using Normal, I's complement and 2' complement subtraction.
- Problem 2 a) Convert each of the following binary numbers to octal and hexadecimal forms: (show your work) (1111110000.1)2 (10100110)2 (101100011001)2 b) Express each of the following octal/hexadecimal numbers in binary and decimal forms: (show your work) (7765) 8 (FB17)16 (A14)16 c) Convert each of the following decimal numbers to BCD: (128)10 (547)10 (1051)10Using excess-15 notation, what is the decimal equivalent of this binary number 1011001110000000. A) 0.123423 B) -0.123423 C) 0.234375 D) -0.234375 E) 0.65342 F) -0.65342 G) 0.37520 H) -0.37520 I) None among the given choicesQ3) A - Convert the Excess-3 to binary number : ( 110001011100.10001010)ex-3 B- convert each Gray code to binary: 1-( 011010001001)G 2-(59)D
- a) Convert the decimal number - 210 into a signed binary number using (1) sign-magnitude method (2) 1's complement method (3) 2's complement method marks) b) If the above decimal number is positive, that is + 210, then convert it to a signed binary number using 1 's complement method (0.5 mark) c) Do the following binary subtraction: (1.5 marks) 100110110.00111- 010100011.01011 d)Explain difference between RAM and ROM? (2 marks)Q1. Show the implementation of 4 bit binary to gray code (shown in below table) converter using either EPROM or PLA. In Gray code only one bit changes at a time. Binary Gray code Decimal equivalent 0000 0000 1 0001 0001 0010 0011 3 0011 0010 4 0100 0110 5 0101 0111 6. 0110 0101 7 0111 0100 8. 1000 1100 1001 1101 10 1010 1111 11 1011 1110 12 1100 1010 13 1101 1011 14 1110 1001 15 1111 1000Q1/The binary number ( 1011011011011.1110111001101)= ( ) in octal number *
- a) Convert the decimal number - 239 into a signed binary number using (1) sign-magnitude method (2) 1's complement method (3) 2's complement method b) If the above decimal number is positive , that is + 239, then convert it to a signed binary number using 1 's complement method c) Do the following binary subtraction: 101111111.01111- 001011010.10110 d)Explain Types of RAM?(a) Perform binary addition of the following numbers: 110111101.11011+ 100001000.01010Using excess-15 notation, find the decimal equivalent of this binary number 0011101100000000.