PBL 1: An enzyme with a Km = 1 X 102 M was assayed to convert the substrate withinitial concentration of 3 X 10$M. Find the time required to convert 70% of substrate when Vmax = 2.167M/min.KmInSo1- (So – S)t =VmaxS' VmaxS = So - xS,

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ncentration of 3 X 10 M. Find the time required to convert 70% of substrate when Vmax = 2.167 M/min. PBL 1: An enzyme with a Km = 1 X 10² M was assayed to convert the substrate with initial co Km So In (So-S) Vmax t = Vmax S = So - xSo

ncentration of 3 X 10 M. Find the time required to convert 70% of substrate when Vmax = 2.167 M/min. PBL 1: An enzyme with a Km = 1 X 10² M was assayed to convert the substrate with initial co Km So In (So-S) Vmax t = Vmax S = So - xSo

Chemistry for Today: General, Organic, and Biochemistry

9th Edition

ISBN:9781305960060

Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen

Publisher:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen

Chapter20: Enzymes

Section: Chapter Questions

Problem 20.45E

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