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- Show that i = 1.06 x 10-34 J-s = 6.59 x 10-16 eV-s.Use the graph below to answer the following question: Maximum Kinetic Energy of Ejected Photo-electron versus Incoming Frequency Maximum Kinetic Energy (eV) wŃ÷0-Nw $10 11 Frequency (E14 Hz) What is the work function of the experimental photo-missive material?Q.1/ Prove that: ni = /N.Ny e-K Eg 2KT Using Eg = Ec- Ev
- A helium ion has one electron in the n=1 orbital. How much energy is necessary to raise this electron to the n=3 orbital? Question 6 options: 13.6 eV 48.4 eV 53.7 eV 54.4 eVDetermine the Fermi energies for (a) Mg, (b) Na, and (c) Zn.1. V R P 1 2 2 3 10 120 3 2. V R 1 30 90 3 10 3. in V R P 1 10 3 2 2 3 T 40 co
- Q.1/ Prove that: ni = Nc Ny e- Using Eg Ec- Ev1. Using the equation p-n+ N – N = 0 and assuming ND = Np and N4 = N4, calculate and plot (a) n versus T , (b) n versus 1/T, and (c) Ef-E¡ versus T for Si for 250 K5. A carbon nucleus and an iron nucleus are initially located 5.60 nm apart from one another. How much work would it take to move the carbon nucleus to a new distance of 2.11 nm from the iron nucleus? 112.7 eV 53.0 eV 66.3 eV 92.8 eVQ.1/ Prove that: ni = NcNy ¯KT KT Using Eg = Ec- Ev Solution: n.p = ni²i provided a solution for the same problem but while using 5.26 T instead of 5.37 T. In the solution provided it gives the answer in eV but for my question, i need the answer to be in micro electron Volt (μeV).A helium ion has one electron in the n=2 orbital. How much energy is necessary to liberate the final electron from this ion? a) 13.6 eV b) 18.1 eV c) 27.2 eV d) 54.4 eV e) None of the other responses are correct.SEE MORE QUESTIONS