My teacher said that the equation v(t) for Vcap (in image) will be V = -1/C integral of i(t) + v(initial). My question is, my teacher has said that the '-' infront of the 1/C is because the current flows into the negative terminal of the capacitor. But in the answer my teacher has put v(initial) as +20 and not -20, even though the 20V across the capacitor is also negative to positive as shown in the image. So why is the v(initial) put as +20 and not -20? Thank you.

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My teacher said that the equation v(t) for Vcap (in image) will be V = -1/C integral of i(t) + v(initial). My question is, my teacher has said that the '-' infront of the 1/C is because the current flows into the negative terminal of the capacitor. But in the answer my teacher has put v(initial) as +20 and not -20, even though the 20V across the capacitor is also negative to positive as shown in the image. So why is the v(initial) put as +20 and not -20? Thank you.
1.6+
MF.
Vcop
اد
+20v
It=o
T
No
+
BB
Transcribed Image Text:1.6+ MF. Vcop اد +20v It=o T No + BB
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