lim h--->0 (f(2+h)-f(2)) / h , where f(x)=4x+8

Q: lim x-->-1, lim x-->-1+, lim x-->-1-,

A:

Q: Limx-->9 = X -9/ (X)1/2 -3

A: We will first cancel out the irrational factor at the denominator. And then we will check if the…

Q: lim                                          (9x/(9x+8))^9x x approaches  infinity using…

A: Given, We have to calculate the limit.

Q: |4-x²| (2) limx--2- (x + 2) 2-x

A: Given function is: f(x)=(x+2)4-x22-x…

Q: Find the limits

A:

Q: lim x approaches 2 (-x^2 + 5x - 2)

A: Given, limx→2-x2+5x-2 To solve the above limit.

Q: lim x---2, x2 - 4/x - 2

A: We have to find the limit: limx→2x2-4x-2 This is 00 indeterminate form of the limit. Rewriting the…

Q: x² – 9 - lim x--3 x² + 2x – 3

A: The given function is limx→-3x2-9x2+2x-3

Q: lim х>1 \x-1 X→1 Inx,

A:

Q: lim x approaches 2 .............. 2x + 5/[11 - x^3]

A: here we have to find the limit.  A=limx→22x+511-x3

Q: lim 2x2 + 7x +5 X-> -I x+1 lim 16 (Titx -1) | Xー76 lim 2x 3-54 X-7 3 X2-9 lim スーフ4 Nin -(ニル) x2-16…

A:

Q: lim x approaches -3  x + 3 /[x2 + 4x + 3]

A: Given: limx→-3x+3x2+4x+3 Apply the limits. limx→-3x+3x2+4x+3=-3+3-32+4(-3)+3=09-12+3=00 As, it…

Q: Lim x approaches to - infinity (5-1/x)

A:

Q: 2-Lim メ→」 X'+ 3 X²-5

A: Our Aim is to evaluate the limit in the expression given below:-limx→1 x4+3x2-5 -(i)

Q: lim x approaches 2/3 .............. (8 - 3s)(2s - 1)

A: We have to find the limit: limx→238-3s2s-1 This is determinate form of limit so we just have to put…

Q: limit (x-> infinity) ({2-x)(3-2x)]/ [(x-1)(4x+3)]

A:

Q: lim x approaches 9 ........ [(x)^1/2 - 3]/(x - 9)

A: limx→9 x-3(x-9)When put x=9, then00 form occur

Q: lim f(x). V5-2x2 <f(x)< V5-x² for -15xs1, find

A: Since both the function lies in interval for x=0. Hence let us find the interval  for the first…

Q: Lim x->4 (x2-3x-4)/ (x-4)

A:

Q: x2 -x-2 lim 12 x- 2x X-2

A:

Q: lim 1/x^2 - 1 = infinity x--> 1+, M = 1000, find largest δ > 0

A: Use the definition of limit

Q: 1. lim (3x + 2) X--3 2. lim(1-x2) -2x2+ 4) X-1 3. lim(3x

A:

Q: V2x2 — х — 1 — Vx — 1 - - - lim x→1 32 - x3 + х — Vx2 +x O A) 2 В) 1 C) none O D) -1 O E) -4

A: we have to evaluate the following limit . For this we can use rationalisation

Q: 2x2 – 12x 1. lim 1-6 r2 +x - 42 3- V25- 2 2. lim 1--4 r+4 3. lim

A:

Q: x-2 6. lim x-2-2-V4x-x²

A: To find:  limx→2- x-22-4x-x2

Q: lim x→2 f(x), where f(x) =    10  −  2x    if x < 2 x2  −  x    if x ≥ 2

A:

Q: Lim            [4(2x-1)2-196]/(x+3) x-&gt;-3

A: Given that the limit is

Q: lim x approaches 6 .............. (x^3 - 2x^2 + 4x + 8)

A: We need to lim x approaches 6 .............. (x^3 - 2x^2 + 4x + 8)

Q: limit of x to infinity Square root(x^2-2x+1)-x

A:

Q: (а) 5x-3 – 4 (i) Lim x-00 2x-2 +9 (х — 3)2 (ii) Lim x-00 x2 7- 2x – 3 2

A:

Q: 28. lim x -2 x-4 V2+パ-V2-x 29. lim

A:

Q: V1-x3 15. lim x-1- V1-x2

A: the given limit is: limx→1-1-x31-x2 we have to evaluate the given limit.

Q: \lim_{x\rightarrow 7}\frac{x^2-5x-24}{x^2-4x-32}x→7lim​x2−4x−32x2−5x−24​

A: find out the limits of  a)limx→7 x2-5x-24x2-4x-32 b)limx→7x2-4x-32x2-5x-24

Q: 34. lim 2-x 35. lim vx -x 36. lim vx-x 140

A:

Q: lim 4 square root x -3/x-81 x-->81

A:

Q: х* — 2х lim 2 x→2 X х — 4 - 4

A:

Q: f -3 -2 -1 -2 -3 2.

A:

Q: x-x-2 6. lim エ→2 (x- 2)² 4-V16+h 9. lim

A: 6. The limit does not exist. 9. The limit is, (- 1/8)   The detailed solution is as follows below:

Q: Determining limits analytically Analyze

A: Given: limx→-4+-x3+5x2-6x-x3-4x2

Q: (а) 5x-3 – 4 (i) Lim- x-00 2x-2 +9 (х— 3)2 (ii) Lim X-00 X T- 2x – 3

A:

Q: lim メ-2 ー×t6-× 2. 12-X X +6

A: Solving

Q: \lim_(x->-\infty )(x^(2)+ x - 5)/(1-2x-x^(3))

A:

Q: lim (√x²+4) x--> 0

A: limx→0x2+4

Q: lim cosx x-0 x2-x+3 1-Vx-6 lim X-7 x-7

A:

Q: lim x>-3- x² +2xr-3 a. X- 7X b. lim x>-3+ x2 +2x-3 lim x>-3 x² +2x-3 C. X- ,X

A:

Q: 5x-3 – 4 (i) Lim: X-00 2x-2 + 9 (x – 3)2 (ii) Lim - 2x- 3 2

A: (i)

Q: Limit (x-> infinity) [(3-x2 )/(4+3x-x2)]

A: We have to find

Q: lim (x2 + 2)sechx X→+0

A: