HOW TO MAKE ID START FROM 5 instead of 2 CREATE TABLE "arena"( "id" integer not null GENERATED ALWAYS AS IDENTITY, "event_date" date not null unique, "people_count" integer not null, CONSTRAINT "id_pkey" PRIMARY KEY ("id")); INSERT INTO "arena"("event_date","people_count") VALUES ('2022-03-01',10),('2022-03-02',109),('2022-03-03',150),('2022-03-04',99),('2022-03-05',145),   ('2022-03-06',1455),('2022-03-07',199),('2022-03-09',188) SELECT * FROM "arena"; SELECT * FROM "arena" WHERE "people_count" >=100 ORDER By "arena" ASC

Oracle 12c: SQL
3rd Edition
ISBN:9781305251038
Author:Joan Casteel
Publisher:Joan Casteel
Chapter6: Additional Database Objects
Section: Chapter Questions
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HOW TO MAKE ID START FROM 5 instead of 2

CREATE TABLE "arena"(
"id" integer not null GENERATED ALWAYS AS IDENTITY,
"event_date" date not null unique,
"people_count" integer not null,
CONSTRAINT "id_pkey" PRIMARY KEY ("id"));

INSERT INTO "arena"("event_date","people_count")
VALUES ('2022-03-01',10),('2022-03-02',109),('2022-03-03',150),('2022-03-04',99),('2022-03-05',145),
  ('2022-03-06',1455),('2022-03-07',199),('2022-03-09',188)
SELECT * FROM "arena";

SELECT * FROM "arena"
WHERE "people_count" >=100
ORDER By "arena" ASC

 

 

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is there any other way to do it without changing the create table instances and just do everything under this part?

SELECT * FROM "arena"
WHERE "people_count" >=100
ORDER By "event_date" ASC

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Follow-up Question

so i want only this part to start from 5

SELECT * FROM "arena"
WHERE "people_count" >=100
ORDER By "arena" ASC

 

Solution
Bartleby Expert
SEE SOLUTION
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