Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs.Output FormatOutput a single line containing the fastest time to get to square N from square 1.Sample Input 05 2 1 4 13Sample Output 06Explanation 0The optimal answer is to:RUN to square 2 (+2 seconds). Sonic now has 1 energy.DASH to square 3 (+1 second). Sonic now has 0 energy.RUN to square 4 (+2 seconds). Sonic now has 1 energy.DASH to square 5 (+1 second). Sonic now has 0 energy.Total time is 6 seconds.Sample Input 15 4 2 10 0Sample Output 112Explanation 1The optimal answer is to:RUN to square 2 (+4 seconds). Sonic now has 1 energy.RUN to square 3 (+4 seconds). Sonic now has 2 energy.DASH to square 4 (+2 seconds). Sonic now has 1 energy.DASH to square 5 (+2 seconds). Sonic now has 0 energy.Total time is 12 seconds.Sample Input 27 1 5 0 21 2Sample Output 26The actual codedef solve(n,a,b,c,k,slippery): # compute and return answer here n, a, b, c, k = list(map(int,input().rstrip().split(" ")))slippery = [] if k == 0 else list(map(int,input().rstrip().split(" ")))print(solve(n,a,b,c,k,slippery)) Sonic the Hedgehog is on a straight track. The track can be represented as N squares as follows:1 234 5 |…....Sonic starts at square 1 and is trying to get to square N as fast as possible. At the beginning, Sonic is alsostoring 0 energy.At each point, Sonic can simply move at his normal running speed, which takes A seconds to go to the nextsquare. Using this move will allow Sonic to store 1 energy.If Sonic has at least 1 energy stored, he can spin dash to the next square, which will take B seconds. Using aspin dash will reduce Sonic's energy by 1.There are K squares that are slippery. If Sonic uses spin dash while standing on these squares, he will slip andfall down. He will then have to get back up and still go to the next square. Getting back up adds C seconds.Note that although Sonic slipped, this still uses up 1 energy, but he will still be in the same square.For example, if square 5 is slippery and Sonic has 7 energy stored, using spin dash there will cause him to slip,reduce him to 6 energy, and will take him C seconds to get back up. When he gets up, he is still in square 5.What is the fastest time Sonic can reach square N given that he uses spin dashes optimally?Input FormatInput consists of a single test case beginning with one line containing three space-separated integers N, A, B,C, and K.• N is the goal square.• A is the time to go to the next square using normal speed.• B is the time to go to the next square using spin dash on a non-slippery square.• C is the time to get back up after falling due to spin dashing on a slippery square.• K is the number of slippery squares.The next line contains K space-separated integers S; indicating the indices of the slippery squares.Constraints1 ≤ S₂ ≤ N≤2.10³0 < A, B, C < 10⁹0

Time complexity is a measure of the amount of time it takes for an algorithm to complete its task,…

Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Output Format Output a single line containing the fastest time to get to square N from square 1. Sample Input 0 5 2 1 4 1 3 Sample Output 0 6 Explanation 0 The optimal answer is to: RUN to square 2 (+2 seconds). Sonic now has 1 energy. DASH to square 3 (+1 second). Sonic now has 0 energy. RUN to square 4 (+2 seconds). Sonic now has 1 energy. DASH to square 5 (+1 second). Sonic now has 0 energy. Total time is 6 seconds. Sample Input 1 5 4 2 10 0 Sample Output 1 12 Explanation 1 The optimal answer is to: RUN to square 2 (+4 seconds). Sonic now has 1 energy. RUN to square 3 (+4 seconds). Sonic now has 2 energy. DASH to square 4 (+2 seconds). Sonic now has 1 energy. DASH to square 5 (+2 seconds). Sonic now has 0 energy. Total time is 12 seconds. Sample Input 2 7 1 5 0 2 1 2 Sample Output 2 6 The actual code def solve(n,a,b,c,k,slippery): # compute and return answer here n, a, b, c, k = list(map(int,input().rstrip().split(" "))) slippery = [] if k == 0 else list(map(int,input().rstrip().split(" "))) print(solve(n,a,b,c,k,slippery))

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Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs.

Output Format
Output a single line containing the fastest time to get to square N from square 1.

Sample Input 0
5 2 1 4 1
3

Sample Output 0
6

Explanation 0
The optimal answer is to:

RUN to square 2 (+2 seconds). Sonic now has 1 energy.
DASH to square 3 (+1 second). Sonic now has 0 energy.
RUN to square 4 (+2 seconds). Sonic now has 1 energy.
DASH to square 5 (+1 second). Sonic now has 0 energy.

Total time is 6 seconds.

Sample Input 1
5 4 2 10 0

Sample Output 1
12

Explanation 1
The optimal answer is to:

RUN to square 2 (+4 seconds). Sonic now has 1 energy.
RUN to square 3 (+4 seconds). Sonic now has 2 energy.
DASH to square 4 (+2 seconds). Sonic now has 1 energy.
DASH to square 5 (+2 seconds). Sonic now has 0 energy.

Total time is 12 seconds.

Sample Input 2
7 1 5 0 2
1 2

Sample Output 2
6

The actual code

def solve(n,a,b,c,k,slippery):
# compute and return answer here

n, a, b, c, k = list(map(int,input().rstrip().split(" ")))
slippery = [] if k == 0 else list(map(int,input().rstrip().split(" ")))
print(solve(n,a,b,c,k,slippery))

Sonic the Hedgehog is on a straight track. The track can be represented as N squares as follows:
1 2
3
4 5 |…....
Sonic starts at square 1 and is trying to get to square N as fast as possible. At the beginning, Sonic is also
storing 0 energy.
At each point, Sonic can simply move at his normal running speed, which takes A seconds to go to the next
square. Using this move will allow Sonic to store 1 energy.
If Sonic has at least 1 energy stored, he can spin dash to the next square, which will take B seconds. Using a
spin dash will reduce Sonic's energy by 1.
There are K squares that are slippery. If Sonic uses spin dash while standing on these squares, he will slip and
fall down. He will then have to get back up and still go to the next square. Getting back up adds C seconds.
Note that although Sonic slipped, this still uses up 1 energy, but he will still be in the same square.
For example, if square 5 is slippery and Sonic has 7 energy stored, using spin dash there will cause him to slip,
reduce him to 6 energy, and will take him C seconds to get back up. When he gets up, he is still in square 5.
What is the fastest time Sonic can reach square N given that he uses spin dashes optimally?
Input Format
Input consists of a single test case beginning with one line containing three space-separated integers N, A, B,
C, and K.
• N is the goal square.
• A is the time to go to the next square using normal speed.
• B is the time to go to the next square using spin dash on a non-slippery square.
• C is the time to get back up after falling due to spin dashing on a slippery square.
• K is the number of slippery squares.
The next line contains K space-separated integers S; indicating the indices of the slippery squares.
Constraints
1 ≤ S₂ ≤ N≤2.10³
0 < A, B, C < 10⁹
0<K<N
All S, are guaranteed to be unique.

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