In this challenge you should repeat a specific given char x times. Create a function that takes a string and a number as arguments and return a string. Examples repeat ("-", 3) → repeat ("A", 0) repeat ("c", -1) Notes |||| 1111 • Tests can repeat a char 268435440 times, no more. • Repeat should be fast maximum execution time : 5 ms. • Total maximum execution time: 3800 ms. • Native repeat is forbidden. • Using of an existing repeat polyfill too (that's not the challenge objective).
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- ATM machines allow 4 or 6 digit PIN codes and PIN codes cannot contain anything but exactly 4 digits or exactly 6 digits. Your task is to create a function that takes a string and returns true if the PIN is valid and false if it's not. Examples validatePIN("1234") ➞ true validatePIN("12345") ➞ false validatePIN("a234") ➞ false validatePIN("") ➞ false Notes ● Some test cases contain special characters. ● Empty strings must return false.Complete the function below that takes in three integers (a,b,c) and returns the number of integers between a and b (inclusive of the endpoints) that are divisible by c. Make sure it tests a and b for divisibility by c! In [ ]: defhow_many_divisible(a,b,c):counter=0# YOUR CODE HEREraiseNotImplementedError()returncounter In [ ]: assert how_many_divisible(10,20,5) == 3 assert how_many_divisible(30,77,7) == 7 PYTHON jYPYTERCreate a function which returns the type of triangle, given the side lengths. Return the following values if they match the criteria. • No sides equal: "scalene" • Two sides equal: "isosceles" • All sides equal: "equilateral" • Less or more than 3 sides given: "not a triangle" Examples get_triangle_type([2, 6, 5]) "scalene" get_triangle_type([4, 4, 7]) "isosceles" get_triangle_type([8, 8, 8]) "equilateral" get_triangle_type([3, 5, 5, 2]) → "not a triangle"
- Plus x: A first function Assign y with 5 plus x. Ex: If x is 2, then y is 7. If x is 19, then y is 24. Note: Some challenge activities require completing a function (as above), or writing a new function. You can create test calls to the function in the "Code to call your function" window, then press "Run". Try appending this call to that window: IncreaseValue(9) When done writing and testing your function, press "Submit for Assessment", which will automatically apply various test calls to your function.Escape from a vertical tab using this method. Is there any way to get around this? This function returns non-zero if char is a letter of the alphabet; else, it returns zero. O is a set of letters () """""""" () In other words () Unless char is a space, this function always returns 0 unless char is a punctuation character. issymbol O ispunctuation) O isspecial 0 ispunctuation) ()Assign y with 5 plus x. Ex: If x is 2, then y is 7. If x is 19, then y is 24. Note: Some challenge activities require completing a function (as above), or writing a new function. You can create test calls to the function in the "Code to call your function" window, then press "Run". Try appending this call to that window: Increase Value(9) When done writing and testing your function, press "Submit for Assessment", which will automatically apply various test calls to your function.
- PHP ATM machines allow 4 or 6 digit PIN codes and PIN codes cannot contain anything but exactly 4 digits or exactly 6 digits. *With user input ($pinNumbers), create a function that takes a string and returns true if the PIN is valid and false if it's not. Examples validatePIN("$1234") ➞ true validatePIN("12345") ➞ false validatePIN("a234") ➞ false validatePIN("") ➞ false Notes ● Some test cases contain special characters. ● Empty strings must return false.In Python, The function add_char_counts takes three parameters: a string s and two strings of length 1, char1 and char2, and returns the total number of times either char1 or char2 appears in s. For example, the word "scallions" has 2 s's and 1 n, so add_char_counts("scallions", "s", "n") returns 3. Hint: Use a string method to help solve this problem (count). You do not need an accumulator. For example: Test Result print(add_char_counts('Indiana', 'a', 'b')) 2 print(add_char_counts('BAHAMAS', 'A', 'B')) 4 print(add_char_counts('Mississippi', 'i', 'M')) 5 print(add_char_counts("spam spam spam spam", "s", "p")) 8The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…
- Create a task that takes a different number of arguments, each argument representing the number of items in the group. The function should return the number of permissions (combinations) of options you would have if you selected one item per group. Examples combination (2, 3) ➡ 6 -> combination (3, 7, 4) combination (2, 3, 4, 5) - 120 Solve in JS -84Create a program that: 1. Prompts the user to enter a string. 2. Use ANY method you'd like to remove all the vowels from the string (string function substring, accessing the string characters as arrays, etc.), creating a new string. 3. Output the new string with all the vowels removed. 4. The program MUST contain two functions-- (1) to remove all the vowels from the string, i.e., create a new string from the old string; (2) to determine if a character is a vowel. 5. Use an enumerated type to evaluate each character to determine if it is a vowel. Hint: Write the program WITHOUT the enumerated type first to get it working.In computational geometry, often you need to find the rightmost lowest point in a set of points. Write the following function that returns the rightmost lowest point in a set of points. const int SIZE = 2;void getRightmostLowestPoint(const double points[][SIZE], int numberOfPoints, double rightMostPoint[]); Write a test program that prompts the user to enter the coordinates of six points and displays the rightmost lowest point.