In Part A of this experiment, you prepare 5 solutions of FeSCN2* [one of them is just a blank solution] according to the reaction below. Fe3+ (aq) + SCN- (aq) → FESCN²+ (aq) We assume that the starting SCN determines the concentration of formed (because Fe3+ is in excess and SCN- is limiting). Calculate the concentration of FeSCN2+ that forms for each of the solution (Beakers 1- 4) and fill out the table below. Show your calculations beneath the table. Beaker 0.200 M 0.0020 M Concentration of Number Fe(NO3)3 (mL] KSCN (mL] H20 [mL] FESCN2+ (M) 1 5.0 5.0 40.0 0.0002 2 5.0 4.0 41.0 0.00016 5.0 3.0 42.0 0.00012 4 5.0 2.0 43.0 0.00008 5 (blank] 5.0 0.0 45.0 181 Show your work for question 1 here: Total volume of all beakers = 50 mL MSCN x V SCN [FESCN2*] = [SCN') = values ok but, you should NOT Use M.VI=M2V2 Total Volume Beaker 1: 0.002 x 5 (FESCN2*] = 50 = 0.0002 M Beaker 2: 0.002 x 4 (FESCN2*] = = 0.00016 M 50 Beaker 3: Show mol ratio 0.002 x 3 (FESCN2"] = = 0.00012M 50 Beaker 4: 0.002 x 4 [FESCN2*] = = 0.00008M 50
In Part A of this experiment, you prepare 5 solutions of FeSCN2* [one of them is just a blank solution] according to the reaction below. Fe3+ (aq) + SCN- (aq) → FESCN²+ (aq) We assume that the starting SCN determines the concentration of formed (because Fe3+ is in excess and SCN- is limiting). Calculate the concentration of FeSCN2+ that forms for each of the solution (Beakers 1- 4) and fill out the table below. Show your calculations beneath the table. Beaker 0.200 M 0.0020 M Concentration of Number Fe(NO3)3 (mL] KSCN (mL] H20 [mL] FESCN2+ (M) 1 5.0 5.0 40.0 0.0002 2 5.0 4.0 41.0 0.00016 5.0 3.0 42.0 0.00012 4 5.0 2.0 43.0 0.00008 5 (blank] 5.0 0.0 45.0 181 Show your work for question 1 here: Total volume of all beakers = 50 mL MSCN x V SCN [FESCN2*] = [SCN') = values ok but, you should NOT Use M.VI=M2V2 Total Volume Beaker 1: 0.002 x 5 (FESCN2*] = 50 = 0.0002 M Beaker 2: 0.002 x 4 (FESCN2*] = = 0.00016 M 50 Beaker 3: Show mol ratio 0.002 x 3 (FESCN2"] = = 0.00012M 50 Beaker 4: 0.002 x 4 [FESCN2*] = = 0.00008M 50
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.107PAE
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