II. Calculate AH, for each of the following (using Table 1). + CHa from the reaction CH.(8) • 20:(8) - CO.(g) 2 H.0(g)+ 192 kcal III. Given the following reactions k S 0: SO: 71.0 kcal 2 so, + 0, Calculate AH, for 2S + 3 0; - 2 SOo, 2 So, + 47.0 kcal
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- 1. Amino acids are the building blocks of proteins. The simplest amino acid is glycine, NH2CH2CO2H. There are three forms in equilibrium with one another. +NH3CH2CO2H(aq) + H2O(l)↔+NH3CH2CO2-(aq) + H3O+(aq) Ka = 4.5 x 10-3 +NH3CH2CO2-(aq) + H2O(l)↔ NH2CH2CO2-(aq) + H3O+(aq) Ka = 1.7 x 10-10 If the pH of a natural system (i.e. your body) is 7.2, in what form is the amino acid found? Justify your answer both with rational as well as a quantitative rationale. 2. Sulfanilic acid, which is used in making dyes, is made by reacting aniline with sulfuric acid: H2SO4(aq) + C6H5NH2(aq)→ + H2O(l) a) If you want to prepare 150.0 g of sulfanilic acid, and you expect only an 85% yield, how many milliliters of aniline should you take as a starting material? (ρaniline = 1.02 g/ml) b) Give the approximate values for the following bond angles in sulfanilic acid: A ______B ______ C ______D _______ c)Give the appropriate hybridization for the following atoms in sulfanilic acid:A ______B ______ C ______D…19. Consider the Ka values for the following acids: Cyanic acid, HOCN, 3.5 × 10 Formic acid, HCHO2, 1.7 × 104 Lactic acid, HC;H5O3, 1.3 × 104 Propionic acid, HC3H5O2, 1.3 × 10-5 Benzoic acid, HC;H5O2, 6.3 x 10-5 Given initially equimolar solutions of each weak acid, which solution will have the highest pH once equilibrium is established? a) НОCN b) HC;H5O2 c) HC3H5O2 d) HC3H5O3 e) HCHO2 f) same pH for allQ1: the solubility-product constant for cadmium carbonate is 2.5*10-14. Calculate the solubility of CdCO; in : a- Water b- A solution that is 0.1M with respect to carbonate ion. Q2: the solubility products for a series of hydroxides are: Kap=4*10-10 Ka=7*10-22 Ka=3*10-24 Kp-4*10-26 BIOOH Be(OH)2 Tm(OH); Hf(OH)4 Which of the above hydroxides has: a- The lowest formal solubility in H2O? b- The highest formal solubility in a solution that is 0.1M with respect to the solute çation ? c- The highest formal solubility in a solution that is 0.1M with respect to OH? Q3: what lead ion concentration is needed to: a- Initiate precipitate of pbSO4 from a solution that is 0.05M with respect to sulfate ion? b- Lower the sulfate ion concentration to 1*10-°M? Q4: drive the formal solubility Of H;A in a solution with a fixed hydronium ion concentration.
- Which of the following salts is most soluble? PBCO3 - Ksp = 1.5 10-13 GalOH)3 - Ksp = 8.6 109 Bizs3 - Ksp = 1.6 * 10-20 Pbl2 - Ksp = 8.7 10-9It is found that 8.70e-09 g of Ga(OH)3 dissolves per 100 mL of aqueous solution at 25 oC. Calculate the solubility-product constant for Ga(OH)3.The Ksp of Y2(CO3)3 at 25 oC is 1.03e-31. What is the molar solubility of Y2(CO3)3?A solution is made initially with 0.270 M HIO: (Kc = 0.170). Once the equilibrium below is established, what is the equilibrium concentration of H ions? %3D HIO: (aq) = H+ (aq) + IO3- (aq) PrtScn F8 Home 114 F5 F4 95 F1 F2 F3 & V %23 24 2 6 4. 9
- 8. Given Ka for CH(CH2) COOH - 1.5 x 105 Mat 298 K. Calculate the pHof a. An aqueous solution of 0.10 M CH,(CH:).COOH (Hint: assume (H,O') = [CH3(CH))CO0) b. An aqueous solution of 0.050 M CH,(CH)»COON and 0.050 M CH(CHa);COOH c. 1Lofthe solution in (b) after the addition of 1.0 x 10 molof solid NaOH.1. Fe(SCN)(H2O)52+ + FeCl3 --> 2. Fe(SCN)(H2O)52+ + KSCN --> 3. Fe(SCN)(H2O)52+ + KCI --> 4. Fe(SCN)(H2O)5²+ + CuSO4 --> 5. Why is the colour of CuSO4 solution blue? 2Predict the products of each reaction, and whether the solution at equilibrium will be acidic, basic, or neutral. At equilibrium the solution is...? reaction acidic N,0,(s) + 3H,0(1) → 0 basic neutral O acidic co, (g) + H,0(1) basic neutral acidic Na, 0 (s) + H,0(1) - 0 basic neutral
- (Q46) Given that the molar solubility of copper (1) chloride (99.00 g/mol) at 25°C is 4.15 x 10-4 mol/L, it follows that at equilibrium: O 41.1 mg of CuCl will exist in one liter of solution as a precipitate 41.1 mg of CuCl will be dissolved in one liter of solution O 41.1 mg of precipitate and 41.1 mg of dissolved ions will be present in one liter of solution O Increasing the temperature would have no effect on solubiility O Diluting the solution would cause precipitation to beginExample - 1 Show by calculation how could you prepare 250 ml of 0.1N Na,CO; from the solid primary standard of Na,CO3, The solution:← < TETNS B Q CAN …. https://app.101edu.co [H3O+] O 2[H3O+] Кс Question 8 of 11 Construct the expression for Kc for the following reaction. CH3COOH(aq) + H₂O(1) ⇒ CH³COO¯(aq) + H³O*(aq) [H3O+]² = Drag the tiles into the numerator or denominator to form the expression. Each reaction participant must be represented by one tile. Do not combine terms. X 2[H3O+]² [H₂O] Q Q [H₂O]² h |a|a|Q| + 2[H₂O] RESET 2[H₂O]²2 [CH3COO-] 2[CH3COO-] [CH3COO-]² 2[CH3COO-1² [CH3COOH] 2[CH3COOH] [CH3COOH]² 2[CH3COOH]² T x + ⠀ Submit