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How R=V/I become ∆R/R = ∆V/V + ∆I/I where R is resistance, V is voltage and I is current. How it derive to ∆R/R = ∆V/V + ∆I/I?
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- Problem 5: A current of I- 2.6 A passes through the circuit shown, where R- 65 3R 5R V) 2R 6R 2R 7R 5R 10R Otheexpertta.com Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the · source, V. Part (b) What is the voltage, V in volts? tan( sin() cotanO a acos cosh0t cosO asin() acotan 4 5 6 sinh() cotanhO *1 23 0 tanh0c O Degrees O Radians CLEAR BACKSPACEA current of I= 4.7 A passes through the circuit shown, where R= 46 N. (a) In terms of R, I, and numeric values, write an expression for the voltage of the source, V. 3R 5R ww ww (b) What is the voltage, V in volts? 2R 6R 2R7R ww 10R 5R 多A current of I = 4.7 A passes through the circuit shown, where R = 46 Q. I 3R 5R ww ww 2R 6R §2RR ww 10R 5R A. In terms of R, I, and numeric values, write an expression for the voltage of the source, V. B. What is the voltage, V in volts?
- Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?Complete the table below. Voltage Current in R, Resistance R, Power in R, Current in R2 SI No (V) Resistance R2 (N) Power in R2 (W) IR: (A) (2) P1 (W) IR2 (A) 1 10 0.102 0.031 20 0.199 0.063 30 0.303 0.092 4 40 0.401 0.122 5 50 0.498 0.153 Average Value of R, () Average Value of R2 (2)Consider the circuit shown in the figure below, where R, = 8.00 N, R, = 7.00 N, and Ɛ = 11.0 V. %3D 10.0 N R2 5.00 N 2.00 N R1 (a) Find the voltage (in V) across R,. V (b) Find the current (in A) in R,. A
- Problem 4: A current of I = 2.3 A passes through the circuit shown, where R = 95 Q. I 3R 5R ww ww 2R 6R 2R 7R ww ww 10R 5R Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the source, V. Expression : V = Select from the variables below to write your expression. Note that all variables may not be required. a, B, 0, a, d, g, h, I, j, k, m, P, R, S, t Part (b) What is the voltage, Vin volts? Numeric : A numeric value is expected and not an expression. V == 10 V and &z = 6 V. Find th In the circuit shown, R, = 3 N, R2 = 2 N, R3 = 5 N, ɛ = 4 V, ɛ2 currents I,, 12 and I3, and the potential difference Vaf using Kirchhoff's rules. %3D %3D %3D C a E1 E2+ Ez+ 12 I3 R1 R2 R3 fCivil Engineering Solve for the total resistance, current of R1, voltage of R2, and power of R3 R Rq 70a R, 682 RIS 240 V R2 50 Rz/300 Ru 59 R$ 50 Rs 40a. R14 10n R 250 Re602 Ro=559 = 82n %3D R1o E
- Measuring Blood Flow. Blood contains positive and negative ions and thus is a conductor. A blood vessel, therefore, can be viewed as an electrical wire. We can even picture the flowing blood as a series of parallel conducting slabs whose thickness is the diameter 5.00 mm of the vessel moving with speed. (See in the following figure.( Figure 1)) Figure X XBX X XX X X X X d 1 of 1 V If you expect that the blood will be flowing at 15.3 cm/s for a vessel 5.00 mm in diameter, what strength of magnetic field will you need to produce a potential difference of 1.00 mV ? Express your answer with the appropriate units. B = Submit Part C 0 R = μA Submit Value X Incorrect; Try Again; 5 attempts remaining T Previous Answers Request Answer = VE ΑΣΦ Determine the volume rate of flow (R). (Note: Although the method developed here is useful in measuring the rate of blood flow in a vessel, it is limited to use in surgery because measurement of the potential & must be made directly across the vessel.)…Question 8 Determine the node voltages in the figure below. Question 10 Question 9 Determine the node voltages, current i, ve, vx and in the figure below. V1 12 R1 Determine the mesh currents 11 +Vx R1 11 0.5 10V va = 2vx R1 1 11 5A ↓ 3ix R2 R3 2 R4 2 Page 3 of 3What is the voltage change if you cross a resistor R in the same direction as the current I? (This means you want Vf-Vi, where Vi is the voltage where the current enters the resistor and Vf, is the voltage where the current leaves the resistor.) What is the voltage change if you cross a resistor R opposite the direction of the current I? (in this case, Vi is the voltage where the current leaves the resistor, and Vf is the voltage where the current enters the resistor.) Which answer is correct? +IR in both cases +IR in the first case and -IR in the second case. +IR in both cases -IR in the first case and +IR in the second case.