How many milliliters of 0.2525 M Ba(OH)2 solution are needed to completely neutralize 47.0 mL of 0.1722 M HI solution? The reaction is Ba(OH)2 + 2 HI - Balz +2 H;0

Chemistry & Chemical Reactivity
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ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section: Chapter Questions
Problem 71PS: If 38.55 mL of HCI is required to titrate 2.150 g of Na2CO3 according to the following equation,...
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How many milliliters of 0.2525 M Ba(OH)2 solution are needed to completely
neutralize 47.0 mL of 0.1722 M HI solution?
The reaction is Ba(OH)2 + 2 HI – Bal2 +2 H20
Transcribed Image Text:How many milliliters of 0.2525 M Ba(OH)2 solution are needed to completely neutralize 47.0 mL of 0.1722 M HI solution? The reaction is Ba(OH)2 + 2 HI – Bal2 +2 H20
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