How did you come to the conclusion for the relative frequencies numbers being 0.5, 0.10, etc? Answer to Problem 5TYThe relative frequency histogram that represents the points scored by the 51 winning teams is as follows:Points scored by the Winning Super Bowl TeamsRelative frequency0.30-0.25-0.20-0.15-0.10-0.05-0.00Explanation of Solution14-20 821-27 1528-34 1435-41 713.5Given info:The data represents the points scored by the 51 winning teams.Calculation:From the problem 'try it yourself 2' the frequency distribution is as follows:Class Frequencyf Mid point Relative frequency42-48 449-55 320.5Σf=51Software procedure:172431384527.534.5Points scored520.160.290.270.140.080.0641.5|Σ=1n48.5

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How did you come to the conclusion for the relative frequencies numbers being 0.5, 0.10, etc?

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.2: Representing Data

Problem 4CYU

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Question

How did you come to the conclusion for the relative frequencies numbers being 0.5, 0.10, etc?

Answer to Problem 5TY
The relative frequency histogram that represents the points scored by the 51 winning teams is as follows:
Points scored by the Winning Super Bowl Teams
Relative frequency
0.30-
0.25-
0.20-
0.15-
0.10-
0.05-
0.00
Explanation of Solution
14-20 8
21-27 15
28-34 14
35-41 7
13.5
Given info:
The data represents the points scored by the 51 winning teams.
Calculation:
From the problem 'try it yourself 2' the frequency distribution is as follows:
Class Frequencyf Mid point Relative frequency
42-48 4
49-55 3
20.5
Σf=51
Software procedure:
17
24
31
38
45
27.5
34.5
Points scored
52
0.16
0.29
0.27
0.14
0.08
0.06
41.5
|Σ=1
n
48.5

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Thank you..why did they use midpoints for the football scores rather than regular numbers as a 14, 20, etc...?

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