A student performed three KHP titrations in Part 1 in order to standardize their NaOH solution. They reported the following measurements: Mass of KHP + Vial Mass of 'Empty' Vial Final Burette Reading Initial Burette Reading Determination #1 16.7538 g 16.2649 g 21.67 mL 0.40 mL Determination #2 14.1709 g 13.5560 g 26.98 mL 0.31 mL Determination #3 15.6625 g 15.0833 g 26.04 mL 0.93 mL How many moles of KHC8H4O4 did they use in their second titration? Report your answer to the correct number of significant figures and only report the numerical value (no units).
A student performed three KHP titrations in Part 1 in order to standardize their NaOH solution. They reported the following measurements: Mass of KHP + Vial Mass of 'Empty' Vial Final Burette Reading Initial Burette Reading Determination #1 16.7538 g 16.2649 g 21.67 mL 0.40 mL Determination #2 14.1709 g 13.5560 g 26.98 mL 0.31 mL Determination #3 15.6625 g 15.0833 g 26.04 mL 0.93 mL How many moles of KHC8H4O4 did they use in their second titration? Report your answer to the correct number of significant figures and only report the numerical value (no units).
Chapter13: Titrations In Analytical Chemistry
Section: Chapter Questions
Problem 13.30QAP
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Transcribed Image Text:A student performed three KHP titrations in Part 1 in order to standardize their
NaOH solution. They reported the following measurements:
Mass of KHP + Vial
Mass of 'Empty' Vial
Final Burette
Reading
Initial Burette
Reading
Determination #1
16.7538 g
16.2649 g
21.67 mL
0.40 mL
Determination #2
14.1709 g
13.5560 g
26.98 mL
0.31 mL
Determination #3
15.6625 g
15.0833 g
26.04 mL
0.93 mL
How many moles of KHC8H4O4 did they use in their second titration? Report your
answer to the correct number of significant figures and only report the numerical
value (no units).
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hi, can you reexplain the
0.6149 g * 1 mol KHP204.22 g= 0.003011 mol KHP
Moles of KHP(KHC8H4O4) used in second titration = 0.003011 mol (Answer)
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