- Given a (2.4) Tree write the fucntion inorder to list all its keys. A node structure consists of Node ( Node child(4]; int key (31: int k;
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- c. Given 2 Arrays of Inorder and preorder traversal. Inorder sequence: {D B E A F C} Preorder sequence: {A B D E C F} Construct a tree and print the Postorder traversal.Design a nonrecursive implementation of a binary tree that maintainsnode data in a Vector, data. In this implementation, element 0 of data references the root (if it exists). Every non-null element i of data finds its left andright children at locations 2i + 1 and 2(i + 1), respectively. (The inverse of theseindex relations suggests the parent of a nonroot node at i is found at locationb(i − 1)/2c.) Any element of data that is not used to represent a node shouldmaintain a null reference. don't copy answer from any ai tool otherwise you will get downvoteConsider the following Binary Tree. root A B D E F C G H K If we perform an postorder traversal, which value is displayed FOURT Enter the node's label (A,B,C,D,E,F,G,H,K) in the space provided.
- We suppose that an AVL tree Complete the following function that performs right rotation. Note that height member of some nodes should be updated. struct node "rightRotate(struct node "y)? In c languageDevelop a function that can quickly determine whether or not nodes u and v in a tree T starting with s are parents and children.Java program that print the nodes as they would bring encountered on the first traversal of the tree
- 4. Construct a binary tree whose nodes in preorder and inorder traversals are given as follows: Preorder Travesal: G, B, Q, A, C, K, F, P, D, E, R, H Inorder Travesal: Q, B, K, C, F, A, G, P, E, D, H, RThe following Program in java implements a BST. The BST node (TNode) contains a data part as well as two links to its right and left children. 1. Draw (using paper and pen) the BST that results from the insertion of the values 60,30, 20, 80, 15, 70, 90, 10, 25, 33 (in this order). These values are used by the program 2. Traverse the tree using preorder, inorder and postorder algorithms (using paper and pen) 3. Write the program in c++, follow its steps, then compile and run. - Compare the results to what you obtained in (2) above. - Try different values class TestBST{public static void main(String []args){int i;int x[] = {60,30, 20, 80, 15, 70, 90, 10, 25, 33};BST t = new BST();for (i=0; i < 10; i++){System.out.print(" Adding: "+x[i]+" to the BST ");t.insert(x[i]);}System.out.println("\nPreorder traversal result:");t.preorder(t.root);System.out.println("\nInorder traversal result:");t.inorder(t.root);System.out.println("\nPostorder traversal result:");t.postorder(t.root);}}class…Draw a single tree whose inorder traversal is and whose postorder traversal is f, a, g, b, h, d, i, c, j, e f.g, a, h, i, d. j, e, c, b
- Write a function label_squarer that mutates a Tree with numerical labels so that each label is squared. def label_squarer(t): """Mutates a Tree t by squaring all its >>> t = Tree(1, [Tree(3, [Tree(5)]), Tr >>> label_squarer(t) >>> t Tree(1, [Tree(9, [Tree(25)]), Tree(49). IL I| | "*** YOUR CODE HERE ***"Given the following struct that represents a binary tree: struct Node { int key: Node "parent; Node "left; Node "right; Nodelint k) : key(k), parent(nullptr), left(nullptr), right(nullptr) (I: 1: Write a recursive function that prints out the nodes in a tree stored using the above structure in order to cout. The function prints the depth (root depth is at 0) and key of that node separated by a colon (Example "O: 10\n" for root with key 10). Your function CAN NOT create any local variables and can only use what is passed to the function. Use the below function signature (NOTE: this is not a class method). void inorderAndDepth(Node "node, int depth)PLease help. Java Yatin is playing PUBG and he has reached a place with a large staircase in front of him.And there is an enemy at each landing of the staircase.This is not the actual staircase. He is looking at the staircase from sideways.The staircase is analogous to a binary tree with each of its nodes as a landing of thestaircase and each of its edges as stairs from one landing to another.Yatin wants to kill the maximum possible number of enemies. He can kill every personhe can see from his position with his suppressed sniper gun. But he can see only thepersons at the leftmost standing at each level and cannot see the rest.Before starting shooting them, he wants to know how many persons he can kill. He isbusy keeping an eye on the enemies. So he wants you to find out the maximum numberof people he can kill from that location by providing you with the analogous a binarysearch tree.[ Note: Players do not change their position after one player has died, i.e. the leftmostnode remains…