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From the following heats of combustion, AH:° = -3119.6 kJ/mol kJ/mol AH:° = -393.5 kJ/mol AH:º= -285.8 kJ/mol CH3OH(1) + 1/2O2(g) → CO2(g) + 2H2O{1) C(graphite) + 0,(g) → Co,(g) H2 (g) + 1/202(g) → H2O1) culate the enthalpy of formation of methanol from its elements: C(graphite) + 2H,(9) + 1/2O2(g) → CH,OH (g)

From the following heats of combustion, AH:° = -3119.6 kJ/mol kJ/mol AH:° = -393.5 kJ/mol AH:º= -285.8 kJ/mol CH3OH(1) + 1/2O2(g) → CO2(g) + 2H2O{1) C(graphite) + 0,(g) → Co,(g) H2 (g) + 1/202(g) → H2O1) culate the enthalpy of formation of methanol from its elements: C(graphite) + 2H,(9) + 1/2O2(g) → CH,OH (g)

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 49E: When 2.50 g of methane burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of...
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6. From the following heats of combustion, AH° = -3119.6 kJ/mol kJ/mol CH3OH(1) + 1/2O2(g) → CO2(g) + 2H2O(I) C(graphite) + 0,(g) → co,(g) H2 (g) + 1/202(g) → H2O1) AH:° = -393.5 kJ/mol AH.º= -285.8 kJ/mol Calculate the enthalpy of formation of methanol from its elements: C(graphite) + 2H,(g) + 1/2O2(g) → CH;OH (g)
Transcribed Image Text:6. From the following heats of combustion, AH° = -3119.6 kJ/mol kJ/mol CH3OH(1) + 1/2O2(g) → CO2(g) + 2H2O(I) C(graphite) + 0,(g) → co,(g) H2 (g) + 1/202(g) → H2O1) AH:° = -393.5 kJ/mol AH.º= -285.8 kJ/mol Calculate the enthalpy of formation of methanol from its elements: C(graphite) + 2H,(g) + 1/2O2(g) → CH;OH (g)
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