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For the reaction Fe3O4(s) + 4H₂ (g) → 3Fe(s) + 4H₂O(g) AH° = 151.2 kJ and AS° = 169.4 J/K The standard free energy change for the reaction of 2.50 moles of Fe3O4 (s) at 337 K, 1 atm would be kJ. This reaction is conditions at 337 K. Assume that AH° and AS° are independent of temperature. favored under standard

For the reaction Fe3O4(s) + 4H₂ (g) → 3Fe(s) + 4H₂O(g) AH° = 151.2 kJ and AS° = 169.4 J/K The standard free energy change for the reaction of 2.50 moles of Fe3O4 (s) at 337 K, 1 atm would be kJ. This reaction is conditions at 337 K. Assume that AH° and AS° are independent of temperature. favored under standard

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter16: Thermodynamics
Section: Chapter Questions
Problem 31E: A reaction has H298=100 kj/mol and S298=250 J/mol K. Is the reaction spontaneous at room...
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For the reaction Fe3O4(s) + 4H₂ (g) → 3Fe(s) + 4H₂O(g) AH° = 151.2 kJ and AS° = 169.4 J/K The standard free energy change for the reaction of 2.50 moles of Fe3O4 (s) at 337 K, 1 atm would be kJ. This reaction is conditions at 337 K. Assume that AH° and AS° are independent of temperature. favored under standard
Transcribed Image Text:For the reaction Fe3O4(s) + 4H₂ (g) → 3Fe(s) + 4H₂O(g) AH° = 151.2 kJ and AS° = 169.4 J/K The standard free energy change for the reaction of 2.50 moles of Fe3O4 (s) at 337 K, 1 atm would be kJ. This reaction is conditions at 337 K. Assume that AH° and AS° are independent of temperature. favored under standard
For the reaction N₂ (g) + 3H₂(g) → 2NH3 (9) AG° = -40.9 kJ and AS = 258 K and 1 atm. This reaction is conditions at 258 K. - 198.7 J/K at favored under standard The standard enthalpy change for the reaction of 1.51 moles of N₂ (g) at this temperature would be kJ.
Transcribed Image Text:For the reaction N₂ (g) + 3H₂(g) → 2NH3 (9) AG° = -40.9 kJ and AS = 258 K and 1 atm. This reaction is conditions at 258 K. - 198.7 J/K at favored under standard The standard enthalpy change for the reaction of 1.51 moles of N₂ (g) at this temperature would be kJ.
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