For the reaction 2N₂ (9) + O₂(g) → 2N₂O(g) AG=214 kJ and AS = -148.5 J/K at 334 K and 1 atm. This reaction is product favored under standard conditions at 334 K. The standard enthalpy change for the reaction of 1.51 moles of N₂ (9) at this temperature would be For the reaction 2H₂O(1)→ 2H₂(g) + O₂(g) AG=483 kJ and AH = 572 kJ at 273 K and 1 atm. This reaction is reactant favored under standard conditions at 273 K. The entropy change for the reaction of 2.18 moles of H₂O(1) at this temperature would be kl. J/K.

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For the reaction
2N₂(g) + O2(g) → 2N₂O(g)
AG = 214 kJ and AS = -148.5 J/K at 334 K and 1 atm.
This reaction is product favored under standard conditions at 334 K.
The standard enthalpy change for the reaction of 1.51 moles of N₂ (9) at this temperature would be
For the reaction
2H₂O(1)→ 2H₂(g) + O₂(g)
AG=483 kJ and AH = 572 kJ at 273 K and 1 atm.
This reaction is reactant favored under standard conditions at 273 K.
The entropy change for the reaction of 2.18 moles of H₂O(1) at this temperature would be
kl.
J/K.
Transcribed Image Text:For the reaction 2N₂(g) + O2(g) → 2N₂O(g) AG = 214 kJ and AS = -148.5 J/K at 334 K and 1 atm. This reaction is product favored under standard conditions at 334 K. The standard enthalpy change for the reaction of 1.51 moles of N₂ (9) at this temperature would be For the reaction 2H₂O(1)→ 2H₂(g) + O₂(g) AG=483 kJ and AH = 572 kJ at 273 K and 1 atm. This reaction is reactant favored under standard conditions at 273 K. The entropy change for the reaction of 2.18 moles of H₂O(1) at this temperature would be kl. J/K.
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