For the cell Ag | AgCl | CI (a = 0.0001),(aCe4+(a = 0.01), Ce³+0.1) | Pt, solve for £ in V, where the standard half-cellpotentials are 0.2225 V for AgCI|CI and 1.45 V forCe4+|Ce³+F = 96,485 C mol-¹

We know according to Nernst equation,Ecell = E0cell - 0.0591/n log [Ce3+]/[Cl-][Ce4+] Where n =…

For the cell Ag | AgCl | Cl (a = 0.0001), Ce4+ (a = 0.01), 0.1)| Pt, solve for ein V, where the standard half-cell potentials are 0.2225 V for AgCI|CI and 1.45 V for Ce++|Ce³+. F = 96,485 C mol-¹ Ce³+ (a

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter18: Introduction To Electrochemistry

Section: Chapter Questions

Problem 18.4QAP

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Question

For the cell Ag | AgCl | CI (a = 0.0001),
(a
Ce4+
(a = 0.01), Ce³+
0.1) | Pt, solve for £ in V, where the standard half-cell
potentials are 0.2225 V for AgCI|CI and 1.45 V for
Ce4+|Ce³+
F = 96,485 C mol-¹

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