For a particular reaction at 148.1 °C, delta G=−1428.51 kJ, and delta S =393.69 J/K . Calculate delta G for this reaction at −62.8 °C. Free energy is related to enthalpy, temperature, and entropy through the equation delta G = delta H -T(delta S) Δ?=Δ?−?Δ? delta H = delta G + T (delta S) Solve for the enthalpy of the reaction. Assume that enthalpy and entropy will not change between the two temperatures. Use the values from the prior scenario (temperature) to determine the new free energy value using the first equation.
For a particular reaction at 148.1 °C, delta G=−1428.51 kJ, and delta S =393.69 J/K . Calculate delta G for this reaction at −62.8 °C. Free energy is related to enthalpy, temperature, and entropy through the equation delta G = delta H -T(delta S) Δ?=Δ?−?Δ? delta H = delta G + T (delta S) Solve for the enthalpy of the reaction. Assume that enthalpy and entropy will not change between the two temperatures. Use the values from the prior scenario (temperature) to determine the new free energy value using the first equation.
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 102SCQ
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For a particular reaction at 148.1 °C,
delta G=−1428.51 kJ, and delta S =393.69 J/K .
Calculate delta G for this reaction at −62.8 °C.
Free energy is related to enthalpy, temperature, and entropy through the equation delta G = delta H -T(delta S)
Δ?=Δ?−?Δ?
delta H = delta G + T (delta S)
Solve for the enthalpy of the reaction.
Assume that enthalpy and entropy will not change between the two temperatures.
Use the values from the prior scenario (temperature) to determine the new free energy value using the first equation.
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