For a particular reaction at 148.1 °C, Δ?=−1428.51 kJ, and         Δ?=393.69 J/K  .  Calculate Δ? for this reaction at −62.8 °C.   Δ?=Δ?−?Δ? thus,  Δ?=Δ?+?Δ?

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
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For a particular reaction at 148.1 °C,
Δ?=−1428.51 kJ, and         Δ?=393.69 J/K  . 
Calculate Δ? for this reaction at −62.8 °C.
 
Δ?=Δ?−?Δ? thus, 
Δ?=Δ?+?Δ?

Assume that enthalpy and entropy will not change between the two temperatures.

Use these values with the new temperature to determine the new free energy value using the first equation.

 
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