Find the vertical force component for the figure 800 N y 50°
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Q: Q3 Find the resultant of force Y 390 Ib IMATHalino.com 12 30 X 300 lb 722 lb Figure P-265 5n
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Q: Example (1):Find the two components of the force (100 X) if: 0 = 30, 120 270° as shown in figure.…
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Q: Find The Resultant For Forces shown in Figure below. 150 N 200 N 150 N 'W=10 Kg \52°.
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A: Given, W1 = 200 N W2 = 60 N W3 = 40 N
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A: given : W = 20000 g = 20kg CW = 45000 g = 45 kg
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Q: Q2: Determine the X and Y components of (100) N force as in figure below
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Q: Example (1):Find the two components of the force (100 X) if: 0 = 30, 120 270 as shown in figure.
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Q: Determine the magnitude and direction of the resultant force using parallelogram law of forces for…
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Q: A 10.5 ft B 200 lb 2 ft 2 ft 1 ft 1 ft 1 ft, F
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Q: Find the normal forces at A, B, and C from the figure below. Each pipe weighs 2500 N. 45°
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Q: a) A steel box is going to be positioned on the wall as shown in Figure la. Determine the value of P…
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Q: /Find the two forces Fbc & Fac as shown * :in the figure below Fab=30 N Fbc
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Q: Example (2): Resolve the 200 N force shown acting on the pin Into components In the (a) X and Y…
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Q: a (1): # the force system shown in figure (1) is in a balanced system, calculate the force and the…
A: We are suppose to solve only one question. Please post other question as a separate question.
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A: Diameter D=4m x=42+3x=5 m Projected area A=4×1=4 m2 ,assume take width of Gate unity
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A: Consider the diagram shown below for the given forces.
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- The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. d 2 Pl CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m С. 62,5 N*m D. Object 1 doesn't exert a torque.The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point P1 11:P1 STATIC MONTHL... Find the resultant force of the following? B. 2 m F = 600 N 3.5 m 0.5 m Fc= 450 N 1.5 m 1m 0.5 m 1.5 m y X II
- QI5: Delermhe The resultant o. The forces shoan in figure () 4 KN 6.A 48KN CAKN 2 KN 54 KN Fy-(15)Calculate the magnitude of the resultant for the force system shown in figure below. 600N SOON 407 30' 400N 300NProblem 3. What is the moment of the 1.4 kN force along the direction of the 1.0 kN force? Express your answer as a magnitude and sketch the direction of rotation about the axis defined by the 1.0 kN force TIGBAO TK 1.0KN X 539 indi 21 150 mm 195 mm 2 4 160 mm 21% ARD 19TO 1.4 kN MEBIRT 0 DAW ITOM 00 1400
- QI5: Delermihe The resultant of The forces shoan in figure () 40, KN 6.0 48N 4 KN CAKN 2 KN 56 KN Fy-(15)Q:Resolve the 170 Ib force of figure below into two components, one along AB and the other parallel to CD 3 A. 4 8. 15 12 170 55. A person pulls on a rope with a force of 100 lbs as shown below. What is the moment about point A as a result of this pulling force? Answer: 3034 ft-lb CW 200 le 10 ft 18 ft Gin A * 40 ft SA
- Q2 Find the resultant of force Y 141.4 N 60 300 N 240 N MATHaling.com 260 N 30 1 m 12 1m Figure P-264 5nThe rectangular framework is subjected to the following non-concurrent system of forces: a 30lb- force below the origin, a 20 lb-force,3ft above the origin and making an angle of30°N of E, a 100lb-force with a horizontal distance of 3ft and a vertical distance of 4ftfrom the origin and making an angle of 45°NW , a 60lb -force with the same distance like the previous force but along the positive x-axis, and a 100lb- force 4ft tothe right of the origin and making an angle of 60° S of W . Determine the magnitude and direction of the resultant, as well as its moment arm relative to the origin.What would be the resultant force F of the triangular distributed load and its location d measured from point A. 60 lb/ft A 3 ft 5 ft 2 ft Select one: Oa.F= 300 lb and d = 2.5 ft Ob.F 150 ib and d= 3.33 ft CF 150 lb and d= 3.67 ft d.F 300 lb and d= 1.67 ft