Find the FALSE statement about the voltaic cell based on the two reduction half-reactions shown below. The concentrations of the ions are [Al3+] = 0.01 M, [Mn2*] =0.1 M.A13+(aq) + 3e¯ - Al(s)E°red = -1.66 VMn2+(aq) + 2e - Mn(s)E°red = -1.18 VAl(s) is a stronger reducing agent than Mn(s)The observed cell potential is 0.49VFor the balanced equation, n = 6 and Q = [AI³+]/ [Mn2+].Using base 10, logQ = -1.The shorthand diagram for this cell is Al(s) | AI3*(aq) || Mn²*(aq) | Mn(s).

1). More the reduction potential stronger will be the oxidizing agent and lesser the reduction…

Find the FALSE statement about the voltaic cell based on the two reduction half- reactions shown below. The concentrations of the ions are [AI3*] = 0.01 M, [Mn2*] = %D О.1 М. Al3+(aq) + 3e – Al(s) E°red = -1.66 V %3D Mn2+(aq) + 2e - Mn(s) E°red = -1.18 V Al(s) is a stronger reducing agent than Mn(s) The observed cell potential is 0.49V For the balanced equation, n = 6 and Q = [Al³+] / [Mn2+]. O Using base 1O, logQ = -1. The shorthand diagram for this cell is Al(s) | Al3*(aq) || Mn2+(aq) | Mn(s).

Find the FALSE statement about the voltaic cell based on the two reduction half- reactions shown below. The concentrations of the ions are [AI3] = 0.01 M, [Mn2] = %D О.1 М. Al3+(aq) + 3e – Al(s) E°red = -1.66 V %3D Mn2+(aq) + 2e - Mn(s) E°red = -1.18 V Al(s) is a stronger reducing agent than Mn(s) The observed cell potential is 0.49V For the balanced equation, n = 6 and Q = [Al³+] / [Mn2+]. O Using base 1O, logQ = -1. The shorthand diagram for this cell is Al(s) | Al3*(aq) || Mn2+(aq) | Mn(s).

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 137CWP: Consider a galvanic cell based on the following half-reactions: a. What is the standard potential...

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Consider a voltaic cell in which the following reaction occurs. Zn(s)+Sn2+(aq)Zn2+(aq)+Sn(s) (a) Calculate E° for the cell. (b) When the cell operates, what happens to the concentration of Zn2+? The concentration of Sn2+? (c) When the cell voltage drops to zero, what is the ratio of the concentration of Zn2+ to that of Sn2+? (d) If the concentration of both cations is 1.0 M originally, what are the concentrations when the voltage drops to zero?
What is the standard cell potential you would obtain from a cell at 25C using an electrode in which Hg22+(aq) is in contact with mercury metal and an electrode in which an aluminum strip dips into a solution of Al3+(aq)?
At 298 K, the solubility product constant for Pb(IO3)2 is 2.6 1013, and the standard reduction potential of the Pb2+(aq) to Pb(s) is 0.126 V. (a) Find the standard potential of the half-reaction Pb(IO3)2(s)+2ePb(s)+2IO3(aq) (Hint: The desired half-reaction is the sum of the equations for the solubility product and the reduction of Pb2+. Find G for these two reactions, and add them to find G for their sum. Convert the G to the potential of the desired half-reaction.) (b) Calculate the potential of the Pb/Pb(IO3)2 electrode in a 3.5 103 M solution of NaIO3.
For each reaction listed, determine its standard cell potential at 25 C and whether the reaction is spontaneous at standard conditions. (a) Mn(s)+Ni2+(aq)Mn2+(aq)+Ni(s) (b) 3Cu2+(aq)+2Al(s)2Al3+(aq)+3Cu(s) (c) Na(s)+LiNO3(aq)NaNO3(aq)+Li(s) (d) Ca(NO3)2(aq)+Ba(s)Ba(NO3)2(aq)+Ca(s)
It took 150. s for a current of 1.25 A to plate out 0.109 g of a metal from a solution containing its cations. Show that it is not possible for the cations to have a charge of 1+.
At 298 K, the solubility product constant for PbC2O4 is 8.5 1010, and the standard reduction potential of the Pb2+(aq) to Pb(s) is 0.126 V. (a) Find the standard potential of the half-reaction PbC2O4(s)+2ePb(s)+C2O42(aq) (Hint: The desired half-reaction is the sum of the equations for the solubility product and the reduction of Pb2+. Find G for these two reactions and add them to find G for their sum. Convert the G to the potential of the desired half-reaction.) (b) Calculate the potential of the Pb/PbC2O4 electrode in a 0.025 M solution of Na2C2O4.
Consider a galvanic cell based on the following half-reactions: a. What is the standard potential for this cell? b. A nonstandard cell is set up at 25C with [Mg2+] = 1.00 105 M. The cell potential is observed to be 4.01 V. Calculate [Au3+] in this cell.
Calculate the standard cell potential of the following cell at 25C. Sn(s)Sn2+(aq)I2(aq)I(aq)
An electrolysis experiment is performed to determine the value of the Faraday constant (number of coulombs per mole of electrons). In this experiment, 28.8 g of gold is plated out from a AuCN solution by running an electrolytic cell for two hours with a current of 2.00 A. What is the experimental value obtained for the Faraday Constant?
The following oxidationreduction reactions are used in electrochemical cells. Write them using cell notation. (a) 2Ag+(aq)(0.50M)+Ni(s)2Ag(s)+Ni2+(aq)(0.20M) (b) Cu(s)+PtCl62-(aq)(0.10M)Cu2+(aq)(0.20M)+PtCl42-(aq)(0.10M)+2Cl(aq)(0.40M) (c) Pb(s)+SO42-(aq)(0.30M)+2AgCl(s)PbSO4(s)+2Ag(s)+2Cl(aq)(0.20M) (d) In a galvanic cell, one half-cell contains 0.010 M HCI and a platinum electrode, over which H2 is bubbled at a pressure of 1.0 atm. The other half-cell is composed of a zinc electrode in a 0.125 M solution of Zn(NO3)2.
The half-cells Ag+(aq. 1.0 M)|Ag(s) and H+(aq, ? M)|H2(1.0 bar) are linked by a salt bridge to create a voltaic cell. With the silver electrode as the cathode, a value of 0.902 V is recorded tor kcell at 298 K. Determine the concentration of H+ and the pH of the solution.

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