Find one cubic metre of concrete (1:3:5). Find the number of bag required?
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- Determine the total length of top bars from the figure shown below. Concrete cover is 40 mm. Use 16 mm diameter main bar 200 mm 200 mm 40 mm 40 mm 40 mm 500 mm 500 mm s00 mm 500 mm 0.30 L1+ +0.30 L2 S2 -0.50 L1 0.50 -L1 =750 m T0.40 -L2 = 3.00 – +0.50 FIGURE 1. Reinforcement Detail MINIMUM DEVELOPMENT LENGHTS AND LAP LENGTHS MIN. LAP LENGTH in tension in compression S1 BARS MIN. DE VELOPMENT LENGTH diameter in mm. 52 51 12 210 375 360 16 210 500 440 11.82 20.94 O 25.36 O 32.66concrete please in 30 minutes.10. a) Find the concrete volume of a 30 ft x 15 ft x 12 in concrete slab. b) Calculate steel quantity (weight in pounds) for the slab shown below. The size of the slab is 30 ft x 15 ft. The main bar is #6@6" OC. Distribution bar is #4@6" OC. Concrete cover is 0.75 in. (Hint: In one-way slab, main bar is parallel to shorter direction and distribution bar is parallel to longer direction) 15' -30'
- 1. Concrete in cubic yards? 2. No. 4 rebar in tons? 3. No. 6 rebar in tons? 4. Formwork in square footage?What is the minimum area (Asmin) for the following concrete beam: b = 10 in, d = 17 in, fy = 60000 psi, and f'c = 5000 psiNote: This is an ACI code check and not required As determined by the moment. Answer in inches^2 and to 3 decimal places. Type your answer...Reinforced concrete is approximately how many times heavier than wood typically used for construction? Question 5 options: 2 3 4 5
- How is concrete consolidated?Q2: Discuss positive aspects of bleeding in concrete.Submit your question to our 24/7 subject matter experts with Masters and PhDs and get a solution in as fast as 30 minutes* Provide clear and step by step solution Using LRFD, PL400x350 mm base plate, W12x120 column, 500x500 mm pedestal, PDL = 1200 kN and PLL = 800 kN. Use A-50 steel and concrete fc’ = 30 MPa. Determine the required base plate thickness.
- Unit for Masonry Works a. Pieces b. Gallons c. Square Meters d. All of the aboveNSCP 2015 Table 405.3.1 provides the calculation of the required strength, U, as follows: U = 1.4D U=1.2D+ 1.6L+0.5 (Lr or R) U= 1.2D + 1.6(Lr or R) + (1.0L or 0.5W) U=1.2D + 1.0W + 1.0L +0.5(Lr or R) U= 1.2D + 1.0E + 1.0L U=0.9D + 1.0W U=0.9D + 1.0E Results of the frame analysis of a certain structure provides the following values of compressive loads for one of the critical members: Gravity Loads: DL = 150 kN, Lr = 60 kN, and LL = 240 kN Wind Load: WL = 50 kN Seismic Load: EL = 40 kN Determine the critical factored load (kN) that will be used in the design of the member.How many cubic yards of concrete are required to construct 31 each 18-inch-diameter, 8-foot-high concrete columns? Include 5% waste. Concrete must be ordered in 1/4 cubic-yard increments.