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Example 2.1 : Calculate the rate of heat loss through a wall of k = 0.70 W/(m K)] 5 m in length, 4 m in height and 250 mm in thickness, if the wall surfaces are maintained at 373 K (100° C) and 303 K (30° C) respectively.

Example 2.1 : Calculate the rate of heat loss through a wall of k = 0.70 W/(m K)] 5 m in length, 4 m in height and 250 mm in thickness, if the wall surfaces are maintained at 373 K (100° C) and 303 K (30° C) respectively.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Example 2.1: Calculate the rate of heat loss Q, through a wall of red [k = 0.70 W/(m K)] 5 m in length, 4 m in height and 250 mm in thickness, if the wall surfaces are maintained at 373 K (100° C) and 303 K (30° C) respectively.
Transcribed Image Text:Example 2.1: Calculate the rate of heat loss Q, through a wall of red [k = 0.70 W/(m K)] 5 m in length, 4 m in height and 250 mm in thickness, if the wall surfaces are maintained at 373 K (100° C) and 303 K (30° C) respectively.
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