Egg 6 (Extra Credit): 26. Parents - Write down the phenotypes in the cross: Green 27. Offspring - List the phenotypes (both color & number): X Pink Green 2 pink 2 pink 1 orange 28. What is the pattern of inheritance: (check one) Dominant/Recessive Incomplete Dominance Codominance Multiple Alleles ex 29. What are the possible genotypes of the parents? (You may not use all the crosses below) X 30. Show the Punnett square for each cross below: ВЬ bb X X 16

Egg 6 (Extra Credit): 26. Parents - Write down the phenotypes in the cross: Green 27. Offspring - List the phenotypes (both color & number): X Pink Green 2 pink 2 pink 1 orange 28. What is the pattern of inheritance: (check one) Dominant/Recessive Incomplete Dominance Codominance Multiple Alleles ex 29. What are the possible genotypes of the parents? (You may not use all the crosses below) X 30. Show the Punnett square for each cross below: ВЬ bb X X 16

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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SUBJECT: GENETICS Topic: Probability 1. Consider albinism a trait to occur in a human family. If two parents areheterozygous for such trait, the probability of having a normally pigmented child is 3//4 and having an albino child is ¼. What is the probability that 2 will be normal and 1 will be albino?
Pedigree 2: A. What is the most likely mode of inheritance of this disease? Choose from: autosomal dominant, autosomal recessive, X-linked dominant, X-linked recessive. B State the genotypes of individuals # 1 #4. C If individual #3 has another daughter with the same partner, what is the probability that this daughter will be affected (show the disease)?
PEDIGREES: Problem (continued) This pedigree shows the inheritance of cystic fibrosis in this family. I • QUESTIONS ••. 5. What is the genotype of individual II-3? Use the letter "f" to 1 2 represent the disease allele. II 1 2 3 6. Individuals II-I and II-2 are sisters. Explain how it is possible for one sister to have cystic fibrosis but NOT the other. III 1 2 3
+ Name Course/Year/Sec LABORATORY EXERCISES IN GENETICS Laboratory Instructor Date Activity Sheet OTHER NON MENDELIAN INHERITANCE 1. In rabbits, coat color is affected by a series of alleles with a hierarchy of dominance such that C+> Ch>Ch> c. Each allele is dominant over all the alleles listed to its right. C+ codes for full color, Ceh codes for chinchilla, Ch codes for himalayan (white with black extremities) and small c codes for albino. A chinchilla rabbit is mated to a himalayan rabbit. Each of these rabbits has one albino parent. What are the phenotypes of the offspring and the probability that each will be produced? Answer 2. The autosomal dominant allele ML specifies a tailless phenotype in cats. This allele is lethal in the homozygous state. A tailless female cat is mated to a tailless male cat. What are the phenotypes of the offspring and the probability that each will be produced? Answer 3. Agouti (A) is wild type and produces alternating bands of pigment on each hair.…
From DNA to Protein and Inheritance Co-Dominance: In co-dominance, the heterozygous individual exhibits the phenotype for both alleles. We used the ABO blood groups as an example of co-dominance. 8. What potential blood types can be present in the offspring if two type "O" mate with one another? (alams 1) Ilgq xal Ligg 9. What are the potential blood types present in the offspring if two parents with type A blood mate with each other? parents 10. What are the potential blood types for offspring that are produced by a parent that is A+ and one that is AB-? Sgningatlo odi nol om sig gonda borooqxs Post-Lab Questions 1. In the human species, polydactyly (the
(Purple) (White) 12. Two plants, both heterozygous for the gene that controls flower color are crossed. Give the expected RATIOS for each genotype and phenotype. Phenotype Ratio - Gentoype Ratio - 13. In guinea pigs, the allele for short hair is dominant over long hair. Two short haired guinea pigs are mated several times. Out of 100 offspring, 25 of them have long hair. What are the probable genotypes of the parents? (Show the cross to prove it!)
1- In garden peas, yellow (Y) seed color is dominant to green (y). Because yellow and green are two different forms of the same gene (seed color), they are alleles. Use a Punnett square to show a cross between two heterozygous pea plants. What are the phenotype(s) of the offspring? What are the genotype(s) of the offspring? 2- In garden peas, yellow (Y) seed color is dominant to green (y). Because yellow and green are two different forms of the same gene (seed color), they are alleles. Use a Punnett square to show a cross between two heterozygous pea plants. What are the phenotype(s) of the offspring? What are the genotype(s) of the offspring? Use the information below to answer questions 3-6 There may be a number of possible alleles for a given gene within a population. In a multiple allele system the dominance relationships between the various alleles must be considered. One of the more familiar examples of a multiple allelic system is that of the human ABO blood group. The gene…
Dihybrid Basics TT or Tt = tall tt = short GG or Gg = green gg = white 1.) A tall green pea plant (TTG9) is crossed with a tall green pea plant (TtGg) FOIL each parent’s genotypes: tall green pea plant (TTGg) short white pea plant (TtGg) How many of the 16 offspring are: tall & green tall & white short & green short & white
100% - Normal teRI 52 Search the menus (Alt+/) 4 2. that a parent The pattern of on to their Heredity (to Inherit) Аny that can be passed or Trait from parent to offspring. the of a trait Allele This allele will be or shown, no Dominant Trait matter what if it is given to the offspring, This allele will be ONLY if there are given to the offspring; both parents Recessive Trait must have and give a copy of the recessive trait for the offspring.to have the trait. Word Bank Illustration Bank characteristic • passes different versions • shown • expressed • traits inherited two copies
Topic: Penetrance. Petal number is controlled by a single gene in merigonias. The gene has a completely dominant wild type allele F that makes a plant have five petals and a mutant recessive six petal allele(f). However the six petal trait is only 50% penetrant. You do the cross Ff x Ff. What fraction of the progeny do you have the 6 petals? what is the meaning for 50% penetrant.
Name: Genetic Crosses that Involve 2 Traits In rabbits, black hair is dominant to brown hair. Also in rabbits, long straight ears are dominant to floppy ears. These letters represent the genotypes and phenotypes of the rabbits: BB = black hair EE = long ears Ee = long ears ee = floppy ears Bb = black hair bb = brown 1. A male rabbit with the genotype BBee is crossed with a female rabbit with the genotype bbEe The square is set up below. Fill it out and determine the phenotypes and proportions in the offspring. How many out of 16 have black hair Be Be Be Be and long ears? How many out of 16 have black hair bE and floppy ears? be How many out of 16 have brown hair and long ears? bE How many out of 16 have brown hair be and floppy ears? 2. Show the cross: GgBb x ggBb How many out of 16 have black hair and long ears? How many out of 16 have black hair and floppy ears? How many out of 16 have brown hair and long ears? How many out of 16 have brown hair and floppy ears?
Classical Mendelian Genetics, Incomplete Dominance, Codominance, and Multiple Alleles 1. Complete the table given below regarding the phenotype and genotype ratios in completely dominant traits. R and r represent the dominant and recessive allele, respectively. Type of Cross rrx rr RR x rr Rrx rr Rrx Rr Genotype Ratio Phenotype Ratio RR x Rr RR X RR *How would the genotype ratios be affected if the mode o inheritance in incomplete dominance? Codominance? 2. In dogs, barer trait is controlled by a dominant gene D and the silent trait by the recessive gene d. Normal tail is dependent on a dominant gene M and the screw m. Give the probable genotypes of the parents in the following crosses: Phenotype of parents Phenotypes of progeny Genotypes of parents Barker Barker Silent Silent normal screw normal normal a. silent normal x silent normal b. barker normal x silent normal 0 0 6 2 7 2 8 3 c. barker normal x silent screw 4 5 5 3 d. barker screw x silent normal 6 0 0 0 e. barker screw x…