During an SAR effort to identify tyrosine kinase inhibitors, it was found that compound 2 was significantly more potent and selective than compound 1. To what might you attribute this improvement in activity and selectivity? Explain. ICS micromolar IC- 0.1 mcromelar
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- Based on your Lineweaver-Burk plot, what is the mode of PaESBL-1 inhibition by NSAMB? What is the equation for the double-reciprocal plot at 20 nMnM NAMB?added ligand concentration of 10 µM is 5 × 10³ s¹. What is the value of the reverse rate constant k_1 = 1 ×10-4 Incorrect Macmillan Learning You have not correctly calculated the value of the reverse rate constant. To begin, calculate the value of k₁ by dividing the rate of receptor-ligand complex formation (the rate of the forward reaction) by the ligand concentration. k₁ = rate forward [L] Then, calculate the value of the reverse rate constant, k_₁, by multiplying the dissociation constant, Kd, and the forward rate constant, k₁. k_1 = Kak₁Crystal structures exist for three neurokinin-1 (NK1) ligand complexes with the following pdb codes (6hll, 6hlo,6hlp). State which is the highest quality crystal structure indicating the criteria you used to evaluate this.
- From experiments in which cells expressing normal myosin II heavy chain were altered to either lack (mhckA-) or overexpress (MHCKA ++) a myosin heavy chain kinase (MHCKA). For answering this question recall the earlier the variants on the myosin II heavy chain, in which three key threonines, normally subject to reversible phosphorylation, were altered in various ways: 3X Ser = Serines in place of Threonines 3X Ala = Alanines in place of Threonines 3X Asp = Aspartate in place of Threonines MHCKA is present at normal levels. Which of the two mutants (mhcp- or MHCP++) would be most likely to have a defect in cytokinesis?What is the relative inhibition of the kinase if the substrate concentration equals KS= 50mM and the concentration of the inhibitor equals KI =250mM?In Figure 4C, we see the inhibition of LRRK2 kinase activity by nanobody 1 (Nb1). Using the Lineweaver-Burke plot, estimate the Km of LRRK2 in the absence of Nb1. Show your work and provide your answer with the correct units.
- From the Hill Plot below, the of the first binding event for the receptor-ligand system under study is: Q1 4 nM 10 μΜ -2 nM 2 nM Calculate the Hill Coefficient from the receptor-ligand binding data below: Q2 4 100 2 3 (077) log 10 8 6 4 2 0 -2 -4 -6 -6 -4 -2 0 2 4 log [L] (nM) 6 8 10Suppose that Protein J which is a hypothetical protein kinase receptor was determined to be related to the progression of cancer through its activation. It was also determined that the protein exists in the active and inactive forms. The said active form is highly similar to the Protein K's conformation. Ligands A, B, and C, which are lead inhibitor compounds, were optimized to inhibit Protein J. The affinities of the ligands are shown in the table. Kp values Active Protein J Inactive Protein J Protein K Ligand A 10 mM 20 nM 5 mM Ligand B 20 nM 10 mM 15 nM Ligand C 20 nM 15 nM 15 nM Question: a. Which of the ligands, based on the table, has the highest specificity in binding to the target Protein J?Suppose that Protein J which is a hypothetical protein kinase receptor was determined to be related to the progression of cancer through its activation. It was also determined that the protein exists in the active and inactive forms. The said active form is highly similar to the Protein K's conformation. Ligands A, B, and C, which are lead inhibitor compounds, were optimized to inhibit Protein J. The affinities of the ligands are shown in the table. Kp values Active Protein J Inactive Protein J Protein K Ligand A 10 mM 20 nM 5 mM Ligand B 20 nM 10 mM 15 nM Ligand C 20 nM 15 nM 15 nM Question: a. Which of the ligands, based on the table, may be expected to be the most potent or have the highest activity against cancer? Explain. b. Which of the ligands, based on the table, may be expected to be least toxic to normal cells? Explain.
- Suppose that Protein J which is a hypothetical protein kinase receptor was determined to be related to the progression of cancer through its activation. It was also determined that the protein exists in the active and inactive forms. The said active form is highly similar to the Protein K's conformation. Ligands A, B, and C, which are lead inhibitor compounds, were optimized to inhibit Protein J. The affinities of the ligands are shown in the table. Kp values Active Protein J Inactive Protein J Protein K Ligand A 10 mM 20 nM 5 mM Ligand B 20 nM 10 mM 15 nM Ligand C 20 nM 15 nM 15 nM Question: Describe the relative binding affinities of Ligand A to Protein K and to the active and inactive forms of Protein J. Determine which will Ligand A bind with the highest, medium, and lowest affinity.If instead of using 3.5 µM myoglobin (receptor) you used half of this (that is, 1.75 µM myoglobin), what would be that value of the Kd, that you calculated ( how would it change)? Please explain so I can solve on my own :) (How does changing concentration of the receptor in a ligand-receptor binding experiment affect the dissociation constant?)EGTA is a chelating agent with high affinity and specificity to Ca2+. By microinjecting a cell with an appropriate EGTA solution, an experimenter can prevent rising cytosolic Ca2+ from rising above 10-7 M. How would EGTA microinjection affect a cell’s response to the ?α-adrenergic and ?β-adenergic pathways?