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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringpublic static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…
- Palindromes - “A palindrome” is a string that reads the same from both directions. For example: the word "mom" is a palindrome. Also, the string "Murder for a jar of red rum" is a palindrome. - So, you need to implement a Boolean function that takes as input a string and its return is true (1) in case the string is a palindrome and false (0) otherwise. - There are many ways to detect if a phrase is a palindrome. The method that you will implement in this task is by using two stacks. This works as follows. Push the left half of the characters to one stack (from left to right) and push the second half of the characters (from right to left) to another stack. Pop from both stacks and return false if at any time the two popped characters are different. Otherwise, you return true after comparing all the elements. Phrases of odd length have to be treated by skipping the middle element like the word "mom", your halves are "m" and "m". - Hint: (without using STL)In the class String, the substring method inserts a String into another String. -True or -FalseFix the code to make it work properly pls // Converts a string to lowercase, and // displays the string's length // as well as a count of letters public class DebugSeven4 { public static void main(String[] args) { String aString = "HELP!! I need to get 37 things DONE today!!"; int numLetters = 0. int stringLength = aString.Length(); System.out.println("In all lowercase, the sentence is: "); for(int i = 0; i < stringLength; i++) { char ch = Character.toTheLowerCase(aString.charAt(i)); System.out.print(ch); if(Character.isLetter(ch)) numLetters--; } System.out.println(); System.out.println ("The number of CHARACTERS in the string is " + stringLength); System.out.println(The number of LETTERS is " + numLetters); } }
- TAKE A LIST OF STRING FROM THE USER AND COUNT THE NUMBER OF UNIQUE ELEMENTS WITHOUT USING THE FOR, WHILE, Do-WHILE LOOPS. PREFERRED PROGRAMMING LANGUAGE: JAVA/C++True or False: The String class’s replace method can replace individual characters, but cannot replace substrings.Target The aim of this work is to use control structures and loops. Read carefully the problem and understand what needs to be done. Read your description is given and when you understand how it works, then start designing its solution and its implementation on the computer applying the syntax and semantics of the language Java programming. Write a LongestDupSubstring.java program that accepts a string as input and compute and print the longest sub-string displayed in two times without overlap (see 5th example for overlap). If there are more from one of such sub-strings, the program displays the first one it finds as well the number of characters in the substring. If there is no substring that appears 2 times, then the program will not print anything. Execution examples (the user's input is red and the longer in length 2 substrings) 1 Example Give a string: again and again Longest substring: again Longest substring size: 5 2 Example Give a string: seven saints and seven dinners Longest…
- Alternate Character DisplayWrite a method that accepts a String object as an argument and then returns the alternate characters as substring starting from index 0. For instance, if the string argument passed is “GREAT”, the method should return “GET”. Demonstrate the method in a program that asks the user to input a string and then passes it to the method.String has only alphabets in it.The String class is a mutable class. O True O False