Diamond is known for being a particularly brilliant stone. The reason behind this is its peculiarly high index of refraction, n = 2.4. A ray of light within a diamond hits the diamond-air (n = 1) interface. Calculate the critical angle for diamond such that the ray be totally internally reflected. Critical angle for diamond-air interface = 0 Once you have determined this, compare the critical angle to the one in the figure below, which is for a glass-air interface? Knowing that glass has a smaller refractive index than diamond, which material will have a larger critical angle. n2=1 n1 =1.5 39° 90° 41.8° 45° 45° Difference between the cirtical angles between the diamond-air and glass-air interface is (report the absolute value of the difference) 0 What is the significance of this comparison with regards to the brilliance of diamond?

Consider a light ray propagates from air medium to the medium of refractive index (0 + 2). If the angle of incidence is 65°, find the angle of refraction (in degree, minutes and seconds). a. Also, find the critical angle for the interface of these mediums. Consider the refractive index air is 1.

Incident white light in air (nair=1) encounters a a piece of plastic as shown in the figure below. The index of refraction for blue light is ng=1.36 and the index of refraction for red light is nr=1.28. After the light passes through the fırst boundary, the blue light undergoes total internal reflection when it encounters the plastic to air boundary from the inside at exactly the critical angle. The red light gets refracted when it encounters the plastic to air boundary from the inside. a) Draw and label a qualitative ray diagram for the light rays for the whole process. b) Find the incident angle of the white light. (you have to really think about what is incident and what is transmitted) c) Using the result from (b), find the angle the red light exits the plastic (no additional points will be taken off if your first result is incorrect). n. 'air

Pin A 90-45-45° prisms is made of lossless glass with n = 1.5. An unpolarized light is incident normally to the interface as shown in figure. What is the PERCENTAGE of incident power coming out of the prism as shown? 7.6 Pout ?

Light travels from air into a fluid which has a refractive index of 1.55. The angle of incidence is 41o.a)Calculate sin of the angle of incidence. Give your answer to 3 decimal places and use it to this accuracy in any subsequent calculations, if needed. Hint: make sure your calculator is on degrees (not radians or grads). b)Calculate the angle of refraction (in degrees). Take the index of refraction of air as 1.Make sure you do all working to at least 3 decimal places. Give your answer to 1 decimal place. c)Light travels out of the fluid into air at the critical angle. What is the angle of refraction (in degrees)? Give your answer as a whole number. d)Calculate the critical angle (in degrees). Give your answer to 1 decimal place.

Given that the glass is semicircular, what happens to the ray of light (bends towards the normal, bends away from the normal, or no refraction) as it passes through the curved surface (only) in cases (a) and (b)? Write answer for each case. Use the figures for additional information.

A ray is incident upon a Piexiglas block. The angle of incidence is (22.0 +/-1.0)deg. The refracted ray is measured to be (15.0 +/- 1.0)deg.   a) Use Senell's law to calculate the index of refraction for the Plexigas    Note: Your final answer must be in radians. I've attached an image of the original question.

Calculate the angle of refraction at the air/core interface, r . critical angle, c and incident angle at the core/cladding interface, i . Will this light ray propagate down the fiber? You have the following data: nair = 1, ncore = 1.46, ncladding =1.43, incident =12o r = 8.2o, c = 78.4o, i = 81.8olight will propagate Formula summery Index of Refraction n= n sin 01= n, sin 0, o = sin1(2) Snell's Law Critical Angle Acceptance angle a= sin1 Numerical Aperture NA = sin a = ni- nị

A) A light ray is incident normally on one face of a triangular prism of glass as shown below. What is the minimum index of refraction of the glass if the light ray is to be totally internally reflected at the slanted surface as shown. Tip: Angles of incidence and reflection are measured relative to the normal to the interface. B) In the index of refraction of the glass is too small some light will be reflected and some light will be refracted at the slanted interface. Which of the numbered suggested refracted rays in the sketch below best represents the actual path of the refracted ray at this interface? Briefly justify your answer. air 11 glass 45" air 450

Examples: Ex.1. Consider a fiber in air with no=1, nj=1.53, and n2=1.5. Calculate and draw a ray diagram for the following: a) The smallest value of the internal angle (i.e. O), b) The maximum angle the ray in air makes with the fiber axis, c) A and NA.