Determine the probability of having homozygous recessive offspring if a homozygous dominant plant is crossed with a heterozygous plant. A. All В. К С. 4 D. None
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Genetic Variation
Genetic variation refers to the variation in the genome sequences between individual organisms of a species. Individual differences or population differences can both be referred to as genetic variations. It is primarily caused by mutation, but other factors such as genetic drift and sexual reproduction also play a major role.
Quantitative Genetics
Quantitative genetics is the part of genetics that deals with the continuous trait, where the expression of various genes influences the phenotypes. Thus genes are expressed together to produce a trait with continuous variability. This is unlike the classical traits or qualitative traits, where each trait is controlled by the expression of a single or very few genes to produce a discontinuous variation.
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- A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. If the first gene is demonstrating dominant epistasis to the second gene, what is the probability that the F1 progeny will expressa. the dominant feature for the second trait?b. the recessive feature for the second trait?c. Neither dominant nor recessive features for the second trait?ibri 12 BIU A - A 4. 11. Mendel crossed peas having round seeds and yellow cotyledons with peas having wrinkled seeds and green cotyledons. All the F1 plants had round seeds with yellow cotyledons. a. What are the genotypes of the parent plants? b. What gametes could be produced by the parent with round seeds and yellow cotyledons? C. What gametes could be produced by the parent with wrinkled seeds and green cotyledons? d. What is the genotype of the F1 plants? e. What gametes could be produced by the F1 plants? hpA. Consider this cross before answering the following questions: A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. If there is complete dominance in the expression of the two traits, what is the probability that the F1 progeny will be a. heterozygous for the first trait? b. expressing the dominant feature of the first trait? c. heterozygous for both first and second traits? d. expressing recessive feature of the second trait? e. recessive for both traits 2. It there is incomplete dominance in the expression of the two traits, what is the probability that the F1 progeny will be a. expressing the dominant feature for the second trait? b. expressing the dominant feature for both traits? c. expressing the dominant feature for the first trait and recessive feature for the second? d. expressing recessive feature for the first trait? e.…
- a. State a hypothesis explaining the inheritance of flower color in painted tongues. b. Assign genotypes to the parents, F₁ progeny, and F2 progeny for all five crosses. c. In a cross between true-breeding yellow and true-breeding lavender plants, all of the F1 progeny are bronze. If you used F₁ plants to produce and F2 generation, what phenotypes in what ratios would you expect? Are there any genotypes that might produce a phenotype that you cannot predict from earlier experiments, and if so, how might this alter the phenotypic ratios among the F2 progeny?Refer to question 4. Assuming complete dominance, the F2 generation will show a phenotypic ratio of _______. a.3:1 b.9:1 c. 1:2:1 d. 9:3:3:1Match the terms with the best description. ___ dihybrid cross a. bb ___ monohybrid cross b. AaBbAaBb ___ homozygous condition c. Aa ___ heterozygous condition d. AaAa
- a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. It there is incomplete dominance in the expression of the two traits, what is the probability that the F1 progeny will be a. expressing the dominant feature for the second trait?b. expressing the dominant feature for both traits?c. expressing the dominant feature for the first trait and recessive feature for the second?d. expressing recessive feature for the first trait?e. expressing recessive feature for both traits?A gardener pertorms a mononybra cross on two heterozygous orange-fruitea tomato plants. Plants expressing the recessive phenotype yield yellow tomato fruits. What percentage of the offspring will produce yellow tomatoes? A:75% B:50% C:100% D:25%
- In a test cross, peas of an unknown genotype are crossed with peas of a known genotype. In this example, smooth peas are the unknown and wrinkled peas are the known (rr). If half of the offspring from that cross are smooth and half are wrinkled, what is the genotype of the unknown plant? O a. Homozygous dominant: RR O b. Homozygous recessive: rr Oc. Incomplete dominance d. Heterozygous dominant: Rr CLEAR MY CHOICEIf a homozygous tall pea plant is crossed with a homozygous shortpea plant, what are the possible genotype and phenotype of theoffspring? Legend: T- tall pea plant t- short pea plant Genotypes of the parents: TT x tt Question : 1. What is the percentage of the offspring having the tall trait.A dihybrid cross between a homozygous dominant for two traits (YYGG) is crossed with a homozygous recessive for two traits (yygg). A. What percentage of the offspring would be YyGg in the F1 generation? B. What is the expected phenotypic ratio of the F2 generation?