Design a project to calculate the of Y according to the following equation x2 x+ Y = 1+ S! n!
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- IN PHP This equates to 5 in xth the power is 25, which is 2 (so x will be 2). Using this example, your task should take 5 and 25 and somehow get 2. Examples logarithm (5, 25) 2 logarithm (2, 64)→ 6 logarithm (2, 4) → 2The square root of any number N>0 can be opproximated by repeated calculation using the formula N = squared_value NG = 0.5 (FG + N/FG) where NG stands for next guess and FG stands for first guess. The value of NG and FG are compared. If the two values are comparably close, then NG is the final answer. If the two values are off, NG becomes FG and the formula is used again to compute FG. After so many iterations, NG and FG will merge. a. Write a function that calculates the square root of a number using this method. The initial guess wilI be the starting value of FG (FG = 1). The function will compute a value for NG using the formula given and returns that value. (Change the name of the functions to something more meaningful) double fun_1 (double FG, double N); b. Write a function that prompts the user for any number N > 0, and returns that value back. The prototype is like follows: double fun_2 ( void ); Now inside the main function, check the difference between NG and FG to see whether…Write a C program that asked the user to enter an integer MAX where 101000. The program then produces the following table of y=x/n where x=1 ..MAX; n=1 ..5 TABLE OF DIVISION 1 | 1 | Y.yyy | 2 | Y.yyy | | Y.yyy | 4 | Y.yyy | 3 | MAX | Y.yyy 2 | 3 Y.yyy | Y.yyy | Y.yyy | Y.yyy | Y.yyy | Y.yyy | Y.yyy | Y.yyy | Y.yyy | Y.yyy | Note: Y.yyy are values of y=x/n displayed with 3 decimals. 4 | 5 | Y.yyy | Y.yyy Y.yyy | Y.yyy Y.yyy | Y.yyy | Y.yyy Y.yyy Y.yyy | Y.yyy
- Water flows through a porous bed at 0.86 m/s. The length of the bed is 5 m. Write PHP Program to calculate the pressure drop across the bed. Use Ergun equation given as; shale dex dat ΔΡ = -Auu – B L Where; 150(1 – a)? A = 1.75(1 – a) ,B = Data: dp = 1.25 x 103m, a = 0.45,u = 1.269 x 10-3 Pa.sWrite a python program that calculate the values of (X + Y) x (X – Y) where X, Y = 0, 1, 2, …, 9and prints the following table:X|Y 0 1 2 3 4 5 6 7 8 90| 0 -1 -4 -9 -16 -25 -36 -49 -64 -811| 1 0 -3 -8 -15 -24 -35 -48 -63 -802| 4 3 0 -5 -12 -21 -32 -45 -60 -773| 9 8 5 0 -7 -16 -27 -40 -55 -724| 16 15 12 7 0 -9 -20 -33 -48 -655| 25 24 21 16 9 0 -11 -24 -39 -566| 36 35 32 27 20 11 0 -13 -28 -457| 49 48 45 40 33 24 13 0 -15 -328| 64 63 60 55 48 39 28 15 0 -179| 81 80 77 72 65 56 45 32 17 0def Mixer(a, b, c): x1 = a // 100 + 1 x2 = a%100 x = str(x1) + str(x2) y1 = b[0:2] y2 = c[2] + c[0] y3 = b[len(b)-2:len(b)] y = y1 + y2 + y3 return x +""+y x = "Super" y = "Mummy" Z = 1921 print(Mixer(z, x, y)) main() Referring to the code above, list the names of three arguments. def main():
- Write a program which find Y : x3 - 2 x if 5>x>1 Y = 5x if x= 0 1 if -1 > x > -5The square root of any number N>0 can be opproximated by repeated calculation using the formula N = squared_value NG = 0.5 (FG + N/FG) where NG stands for next guess and FG stands for first guess. The value of NG and FG are compared. If the two values are comparably close, then NG is the final answer. If the two values are off, NG becomes FG and the formula is used again to compute FG. After so many iterations, NG and FG will merge. a. Write a function that calculates the square root of a number using this method. The initial guess will be the starting value of FG (FG = 1). The function will compute a value for NG using the formula given and returns that value. (Change the name of the functions to something more meaningful) double fun_1 (double FG, double N); b. Write a function that prompts the user for any number N > 0, and returns that value back. The prototype is like follows: double fun_2 ( void ); c. Now inside the main function, check the difference between NG and FG to see…What will be the value of Y given: Y= A.B + (A+B) Given A=1, B= 0.
- Question 2.1 Given a positive integer, N, the '3N+1' sequence starting from N is defined as follows: If N is an even number, then divide N by two to get a new value for N If N is an odd number, then multiply N by 3 and add 1 to get a new value for N. Continue to generate numbers in this way until N becomes equal to 1 For example, starting from N = 3 the complete '3N+1' sequence would be: 3, 10, 5, 16, 8, 4, 2, 1 Write code to ask the user to enter a positive integer (N) in the main() function. Write a function sequence() that receives the integer value N and display the 3N+1' sequence starting from the integer value that was received (entered by the user). The function must also count and return the numbers that the sequence consists of. The returned value must be displayed from the main() function.Write program in PHP language to take 2 number and find the remainder when a dividing by b.if a = 5(00000101), b = 9(00001001), The result of (a&b)= O a. 00000001 O b. 10000000 O C. 01000000 O d. 00000010