Define a function G: RR by the rule G(x) = 2 - 3x for all real numbers x. Is the following a proof demonstrating that G is onto? To prove that G is onto, you must prove that for all y in Y, there exists an x in X such that G(x) = y Proof: y = 2 - 3x Solving for x using algebra, x = (2-y)/3 Plugging x back into G you get, y = 2 - 3((2 - y)/3) Using algebra, y = y so G is onto [as was to be shown]. True False

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter5: Rings, Integral Domains, And Fields
Section5.2: Integral Domains And Fields
Problem 16E: Prove that if a subring R of an integral domain D contains the unity element of D, then R is an...
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Define a function G: RR by the rule G(x) = 2 - 3x for all real
numbers x. Is the following a proof demonstrating that G is onto?
To prove that G is onto, you must prove that for all y in Y, there exists
an x in X such that G(x) = y
Proof:
y = 2 - 3x
Solving for x using algebra, x = (2-y)/3
Plugging x back into G you get, y = 2 - 3((2 - y)/3)
Using algebra, y = y so G is onto [as was to be shown].
True
False
Transcribed Image Text:Define a function G: RR by the rule G(x) = 2 - 3x for all real numbers x. Is the following a proof demonstrating that G is onto? To prove that G is onto, you must prove that for all y in Y, there exists an x in X such that G(x) = y Proof: y = 2 - 3x Solving for x using algebra, x = (2-y)/3 Plugging x back into G you get, y = 2 - 3((2 - y)/3) Using algebra, y = y so G is onto [as was to be shown]. True False
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