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- Consider TDM-based circuit switching with 8000 frames per second and 32 time slots per frame. During each time slot 8 bits are sent. Assuming it is possible to combine several circuits, how many circuits does it take to keep the transmission time of a 1 Mbyte file below 15 seconds?Consider TDM-based circuit switching with 8000 frames per second and 32 time slots per frame. During each time slot 8 bits are sent. What is the shortest time possible (in seconds) to transmit a 1 Mbyte file over the given link?Suppose a 128-kbps point-to-point link is set up between the Earth and a rover on Mars. The distance from the Earth to Mars (when they are closest together) is approximately 55 Gm, and data travels over the link at the speed of light-3 × 108 m/s. (a) Calculate the minimum RTT for the link. X (b) Calculate the delay x bandwidth product for the link. (c) A camera on the rover takes pictures of its surroundings and sends these to Earth. How quickly after a picture is taken can it reach Mission Control on Earth? Assume that each image is 5 Mb in size.
- Please check my answer and correct the part which is need to be foxed.And provide justification for the answer. a) The transmission time of a frame can be calculated as follows: Propagation delay (Tp) = distance/speed = 5km / 200000 km/s = 0.0025ms Transmission time (Tt) = frame size/bandwidth = 10000 * 8bits / (1Mbps * 10 ^ 6) = 0.008sec = 8ms Total time for transmission = 2 * Tp + Tt(since the frame has to travel from A to D and then D to A) = 2 * 0.0025ms + 8ms = 0.005ms + 8ms = 8.005ms The transmission time of the frame from A to D is 8.005 ms. b) The efficiency of the CSMA/CD protocol is given by the formula: Tt is the transmission time of a frame C is the number of collisions, Tp is the propagation time of a signal from one end of the segment to the other. Efficiency = Tt / (C * 2 * Tp + Tt + Tp) Assuming that there are no other stations transmitting or attempting to transmit on the segment, the transmission from A to D will succeed without collisions. Therefore,…Consider a full-duplex 256 Kbps satellite link with a 240 millisecond end-to-end delay. The data frames carry a useful payload of size 12,000 bits. Assume that both ACK and data frames have 320 bits of header information, and that ACK frames carry no data. What is the effective data throughput When using Stop and Wait?5- A synchronous TDM with four 2 Mbps data stream inputs and one data stream output. The multiplexing unit of data is 1 bit. The input bit duration is the output bit duration is the output frame rate is ------- Frame/sec. otansmi Mbps; and us; the output bit rate is natos imeni adi stonl -.oi mibanaine 1. 1. ... 2 Mbps Be eill Frames ilsbit ... 0. 2 Mbps MUX 2 Mbps 1. 1. ... 2 Mbps .. 7- A de pulse train has a peak voltage value of 5 V, a frequency of 4 MHz, and a duty cycle of 30 percent. The minimum bandwidth necessary to pass this signal without excessive distortion is MHz. (Note: to =T*Duty Cycle; T= 1/F) 8- Ten channels, each with a 200 kHz bandwidth, are to be multiplexed together using FDM. The minimum bandwidth of the link is need for a guard band of 10 k Hz between the channels; while the minimum bandwidth of the link is 20 kHz between the channels. KHz when there is a KHz when there is a need for a guard band of 9. If a channel can transmit a range of frequencies from 10 MHz…
- We have 14 sources, each creating 500 characters per second. Since only some of these sources are active at any moment, we use statistical TDM to combine these sources using character interleaving. Each frame carries 6 slots at a time, but we need to add four-bit addresses to each slot. Answer the following questions:(1)What is the size of an output frame in bits?(2)What is the output frame rate?(3)What is the duration of an output frame?(4)What is the output data rate?Two channels, one at 190Kbps and the other at 180Kbps, are to be multiplexed using Pulse-Stuffing TDM with no synchronisation bits. Please respond to the following questions. I Determine the size of frames in bits. ii) Determine the frame rate. iii) Determine the duration of Frame.Four channels, two with a bit rate of 200 kbps and two with a bit rate of 150 kbps, are to be multiplexed using multiple slot TDM with no synchronization bits. Answer the following questions: a. What is the size of a frame in bits? b. What is the frame rate? c. What is the duration of a frame?
- please answer with proper explanation and step by step solution with final answer conclusion. Question: What is the rate in bits/sec to transmit a picture frame of size 460 by 300 bits in 33ms?Consider TDM-based circuit switching with 8000 frames per second and 32 time slots per frame. During each time slot 8 bits are sent. How long (in seconds) does it take to transmit a 1 Mbyte file over one circuit?Four channels are multiplexed using synchronous TDM. The rate of each channel is given by 500 kbps and we use 2-bit units, provide a step-by-step calculation for the following: 1. Input bit duration 2. Input unit rate 3. Output frame rate 4. Output frame size