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The following reaction is first order with respect to (CH3)3CBr and zero order with respect to CH3OH. The rate constant for the reaction is 2.28 x 10-² s¹ at 25°C. (CH3)3CBr + CH3OH (CH3)3COCH3 + HBr a. Write the rate law expression for this reaction. b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of t (CH3)3CBr to react? c. What would the concentration of (CH3)3CBr be after 20.0 minutes? d. What is the half-life for this reaction?

The following reaction is first order with respect to (CH3)3CBr and zero order with respect to CH3OH. The rate constant for the reaction is 2.28 x 10-² s¹ at 25°C. (CH3)3CBr + CH3OH (CH3)3COCH3 + HBr a. Write the rate law expression for this reaction. b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of t (CH3)3CBr to react? c. What would the concentration of (CH3)3CBr be after 20.0 minutes? d. What is the half-life for this reaction?

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 101QRT
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The following reaction is first order with respect to (CH3)3CBr and zero order with respect to CH3OH. The rate constant for the reaction is 2.28 x 10² s¹ at 25°C. (CH3)3CBr + CH3OH (CH3)3COCH3 + HBr a. Write the rate law expression for this reaction. b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of the (CH3)3CBr to react? c. What would the concentration of (CH3)3CBr be after 20.0 minutes? d. What is the half-life for this reaction?
Transcribed Image Text:The following reaction is first order with respect to (CH3)3CBr and zero order with respect to CH3OH. The rate constant for the reaction is 2.28 x 10² s¹ at 25°C. (CH3)3CBr + CH3OH (CH3)3COCH3 + HBr a. Write the rate law expression for this reaction. b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of the (CH3)3CBr to react? c. What would the concentration of (CH3)3CBr be after 20.0 minutes? d. What is the half-life for this reaction?
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for D, how did we get 0.693?

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could you give furthur explination on how C was calculated 

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