Could the characteristic followed in the pedigree be caused by an autosomal dominant disease? Why or why not? ONo, the offspring of 1-3 and I-4 contradict an autosomal dominant inheritance ONo, the offspring of 1-1 and I-2 contradict an autosomal dominant inheritance O Yes, all individuals fit the autosomal dominant inheritance pattern No, the offspring of -3 and 1-4 contradict an autosomal dominant inheritance

Could the characteristic followed in the pedigree be caused by an autosomal dominant disease? Why or why not? ONo, the offspring of 1-3 and I-4 contradict an autosomal dominant inheritance ONo, the offspring of 1-1 and I-2 contradict an autosomal dominant inheritance O Yes, all individuals fit the autosomal dominant inheritance pattern No, the offspring of -3 and 1-4 contradict an autosomal dominant inheritance

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Description: Could the characteristic followed in the pedigree be caused by an autosomal dominant disease?Why or why not?34.O No, the offspring of 1-3 and I-4 contradict an autosomal dominant inheritanceO No. the offspring of 1-1 and I-2 contradict an autosomal

Biology (MindTap Course List)

11th Edition

ISBN:9781337392938

Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Chapter16: Human Genetics And The Human Genome

Section: Chapter Questions

Problem 11TYU

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A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
tion 8: below is the pedigree of inheritance of phenylketonuria (PKU). We will designate the letter Caven for the dominant allele and "p" for the recessive allele. 4 The pedigree shows that the pattern of inheritance for the allele for phenylk ylketonuria is: I. II. 1 III. IV. Autosomal dominant Autosomal recessive X-linked dominant X-linked recessive b. The parents in generation I have how many children: I. 3 Boys II. 3 Girls III. IV. 3 Boys and 1 Girl 3 Girls and 1 Boy c. What is the genotype of individual 1 in generation III: I. PP II. pp III. Pp " O 1 III. 50% E III 1 ▬ 2 2 IV. 25% 1 3 IV. Can be PP or Pp ii. Suppose that a man having type AB blood marries a woman having type O blood. What is the probability that their child will have type A blood? I. 100% II. 75% 2 4 3
the offspring ès) can often be autosomal I 1.1 III ad amalg od no IV 9 OTO 5 0000 anivellor and goje If individual 2 were to marry a woman with no family history of the disease, which of the following would most likely be true of their children? a. All of the children would have the disease. b. None of the children would have the disease. c. Only the sons would have the disease. d. All of the sons would be carriers of the disease. e. None of the daughters would be carriers of the disease.
15 1 point What is the most likely mode of inheritance of the disease depicted in the following pedigree? ||| IV 1 autosomal dominant autosomal recessive 2 N 1 2 2 3 3 4 3 4 5 --D
Genetic Inheritance Patterms Retinitis pigmnentosa (RP) can be autosomal recessive, autosomal dominant, or x-linked. Apparently the dominant forms are often less severe. Eric's form of RP is Usher's Syndrome, which is an autosomal recessive inheritance (i.e., you must get a copy of the defective gene from your Mom and one from your Dad). Autosomal means it is not carried on one of the chromosomes that determines sex. Usher's Type II is recessive, so for Eric this means that both his Mom and Dad are carriers of this condition. His brother, Dirk, does not have any symptoms of RP. Question below - short answer approach Imagine you are a genetics counselor, and Dirk, Erik's brother, comes in to see you. Based on his parents, what are Dirk's possible genotypes for RP? What advice would you give Dirk about the chances of Dirk's children having retinitis pigmentosa if his wife is not a carrier? How would your advice change if his wife fully has the disease? Describe all the possibilities,…
QUESTION 22 Consider whether the mode of inheritance for each of the pedigrees below is autosomal dominant or autosomal recessive Pedigree I Both pedigrees show autosomal dominant modes of inheritance Pedigree I is autosomal dominant while pedigree II is autosomal recessive O Pedigree I is autosomal recessive while pedigree II is autosomal dominant O Both pedigrees show autosomal recessive modes of inheritance QUESTION 23 A Pedigree II The pedigree below shows the inheritance of an X-linked recessive disorder. B TH Quers
PART 3– Sex Linkage Hemophilia is a recessive sex-linked disorder in which an important clotting factor protein (Factor VIII) is not produced in a functional form. Queen Victoria was a carrier of the recessive Factor VIII allele, meaning she carried the allele but was asymptomatic. Recently, historians have discovered that she secretly had an affair with the Austrian Count Chocula, who, unbeknownst to her, was a hemophiliac. Naturally, the Royal Family fought to have this information suppressed, but it was revealed that they had many children together. 1. Using the correct allele notation, write the genotypes for Queen Victoria and Count Chocula. 2. In the Punnett Square below, show the cross between the Queen and the Count. P> PĮ
All the non-shaded individuals are wild type apart from III.1. III.1 has been proven to have the causative mutation for this Autosomal Dominant condition, but they exhibit no symptoms.What is the percentage level of penetrance for the condition in the diagram?
Could this be an autosomal dominant trait? C O yes O no Could this be an autosomal dominant trait? OO O no yes
Cystic fibrosis (CF) is an autosomal recessive condition triggered by the overproduction of stickymucus that clogs the lungs and pancreas. It is a life-threatening disease, but medical advances helpedthe afflicted to live through adulthood. The mother of Claudia died from cystic fibrosis, but her father was normal and never had anyrelative with CF. Her fiancé, Marcus, turned out to be a carrier of the CF allele. What are the genotypes of Claudia and Marcus? Claudia: ________________________ Marcus: _____________________ They planned to have four children. What is the probability that:a. all children will be normal b. at least two will be normal
Cystic fibrosis (CF) is an autosomal recessive condition triggered by the overproduction of stickymucus that clogs the lungs and pancreas. It is a life-threatening disease, but medical advances helpedthe afflicted to live through adulthood.The mother of Claudia died from cystic fibrosis, but her father was normal and never had anyrelative with CF. Her fiancé, Marcus, turned out to be a carrier of the CF allele. What are the genotypes of Claudia and Marcus? Claudia: ________________________ Marcus: _____________________ They planned to have four children. What is the probability that: a. all children will be normal b. at least two will be normal