Convert the regular expression 0(0+1)*11 to an \epsi - NFA in such a way that you are guaranteed that it is correct. Justify your reasoning.
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- The Problem A Zeckendorf number is defined for all positive integers as the number of Fibonacci numbers which must be added to equal a given number k. So, the positive integer 28 is the sum of three Fibonacci numbers (21, 5, and 2), so the Zeckendorf number for k = 28 is three. Wikipedia is a satisfactory reference for our purposes for more details of the Zeckendorf and Fibonacci numbers. In both cases, you do not need to read the entire Wikipedia entry. Your assignment is to write two ARM assembly language functions which calculate Zeckendorf and Fibonacci numbers. Zeck function The first function, which should be named zeck, receives an integer parameter in register zero. This will be the variable k we discussed above. Your code should return the Zeckendorf number for k in register zero when complete. If the parameter k is zero, return zero. If the parameter k is negative, return minus 1. If the parameter k is too large to calculate, return minus 1. Fib function The other function,…please don't copy the answer cuz its not right and clrearConsider the code C={00010, 01100,01011,11010,01010}. What is the minimum distance of C? For what k is the code C k-error detecting? Write the set of error patterns that C can detect?
- Correct answer will be upvoted else downvoted. Each decimal number has a base k same. The singular digits of a base k number are called k-its. How about we characterize the k-itwise XOR of two k-its an and b as (a+b)modk. The k-itwise XOR of two base k numbers is equivalent to the new number framed by taking the k-itwise XOR of their relating k-its. The k-itwise XOR of two decimal numbers an and b is signified by a⊕kb and is equivalent to the decimal portrayal of the k-itwise XOR of the base k portrayals of an and b. All further numbers utilized in the assertion underneath are in decimal except if indicated. When k=2 (it is in every case valid in this form), the k-itwise XOR is as old as bitwise XOR. You have hacked the criminal data set of Rockport Police Department (RPD), otherwise called the Rap Sheet. However, to get to it, you require a secret word. You don't have any acquaintance with it, yet you are very certain that it lies somewhere in the range of 0 and n−1…Consider the regular expressions: R1 = (a | b )* (0*1*) ( a | b )* R2 = (a | b ) (0*1*)*( a | b ) R3 = 01(R2*) Which of the following is true? A. aa ∈ L(R1) and 0101 ∈ L(R3) B. abab0101 ∈ L(R1) and ab0101a ∈ L(R2) C. a000111abab ∈ L(R1) and a01100110a ∈ L(R2) D.a010101a ∈ L(R1) and a010101a ∈ L(R2)Here is the value of X is 1
- Your task is to design automated solvers for the shift and Vigenere ciphers. You must use C as the under- lying programming language, in order to get prepared for the following labs. Each solver should be completely automated, i.e., upon reading a text ,l.e. containing the target ciphertext (given as command-line argument), it should print the encryption key and the decrypted plaintext without any user interaction. Test your code on the following ciphertexts, and answer these questions: 1. What is the key of the cipher? 2. What is the decrypted plaintext?Shift Cipher - Decrypt the following ciphertext:…Convert the following to the other canonical formIn mathematical logic it is known that the “OR” operator is a binary operator between two operands, “p” and “q”, where each one can have either 0 (zero) or 1 (one) as a truth value. Considering the truth table of the “OR” operator, what is the probability of the result of an operation between “p” and “q” resulting in the value “1”? A) ¾ B) ¼ C) ½ D) 1 E) 0
- Can you define less than (<) only using less than or equal to (≤), without using equal (=) and any logical operatorsWe have shown how to use truth tables to determine if two formulas are truth-functionally equivalent.If two formulas F and G are truth-functionally equivalent we introduce another symbol ↔, aptly called thebiconditional. Here is the truth table for the biconditional.p q (p ↔ q)1 1 11 0 00 1 00 0 1Now we shall say that F and G are truth-functionally equivalent if (F ↔ G) is a tautology.There are other properties of two formulas that we are usually interested in besides truth-functionalequivalence. One of these properties is when two formulas are mutually exclusive. We say two formulas Fand G are mutually exclusive if (F ∧ G) is contradictory (unsatisfiable).Now using truth tables determine whether the following formulas are truth-functionally equivalent or mutuallyexclusive.(a) p and ¬p (b) p and ¬¬p (c) ¬(p ∧ ¬q) and (p → q) (d) (¬p ∨ q) and (p → q) (e) ¬(¬p ∨ ¬q) and (p ∧ q) (f) ¬(¬p ∧ ¬q) and (p ∨ q)If b is a unit modulo m and a is another unit with a=b^d (mod m), we say that d is the _________ of a modulo m to the base b and write d =___________.