Consider the indefinite integral + 222 – 29z – 21 da. 1² – 9 The integrand decomposes into the form ar + b+ 3 z + 3 where a = b = c = d = Integrating term by term, we obtain that (4x³ + 2z2 – 29r – 21 da = 22 – 9 +C.

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