Consider the following reaction at equilibrium. NH3 + H₂O. <-> NH4+ + OH What would happen to the equilibrium if we added additional NH3? the concentration of water would increase nothing would happen because this is not a second order reaction the concentration of reactants would be balanced the concentration of products would increase

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.100PAE: 12.100 A reaction important in smog formation is O3(g)+NO(g)O2(g)+NO2(g)K=6.01034 (a) If the initial...
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Consider the following reaction at equilibrium.
NH3 + H2O <
<-> NH4+ + OH
What would happen to the equilibrium if we added additional NH3?
the concentration of water would increase
nothing would happen because this is not a second order reaction
the concentration of reactants would be balanced
the concentration of products would increase
Transcribed Image Text:Consider the following reaction at equilibrium. NH3 + H2O < <-> NH4+ + OH What would happen to the equilibrium if we added additional NH3? the concentration of water would increase nothing would happen because this is not a second order reaction the concentration of reactants would be balanced the concentration of products would increase
Consider the following reaction at equilibrium.
NH3 + H₂O <-> NH4+ + OH
What would happen to the equilibrium if the hydroxide was removed as fast as it was
produced?
the rate of formation of ammonia would decrease
the rate of formation of ammonia would increase
the rate of formation of hydroxide would stay the same
removing of the hydroxide is not possible as it violates the second law of
thermodynamics
Transcribed Image Text:Consider the following reaction at equilibrium. NH3 + H₂O <-> NH4+ + OH What would happen to the equilibrium if the hydroxide was removed as fast as it was produced? the rate of formation of ammonia would decrease the rate of formation of ammonia would increase the rate of formation of hydroxide would stay the same removing of the hydroxide is not possible as it violates the second law of thermodynamics
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