Consider the following initial value problem: dy (t² - 20t+51) = y with y(10) = 1. dt A. Solve the initial value problem (find y as a function of t.) 14 17-t t-3 y = B. On what interval is the solution valid? It is valid for 3 < t < 17 C. Find the limit of the solution as t approaches the left end of the interval. Answer: ∞ D. Find the limit of the solution as t approaches the right end of the interval. Answer:

Q: 2. Graph and find the vertical asymptote of the function: x² + 1 3x - 2x² y =

A: Giveny=x2+13x-2x2

Q: 17. y = x – 2x3 x = 3 Δx = = dx – 0.001

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Q: [ 2 3t+4 dt

A: Topic:- calculus and application of integration

Q: second answer is incorrect

A: Profit=Revenue-Variable cost-Fixed cost

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A: Find the function and their domain

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A: We can find the answer as below.

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A: Here we have to use the concept of derivatives.

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Q: Box your Final answer with a complete solution. Then Graph, emphasize the Limit. 5. lim x-3 x²-5+2…

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A: We can find the answer in the below steps.

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A: Given, p(x)=x·f(x)-g(3x-5)

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Q: Let F(x) = f(g(x)), , where f(-7)=2, f'(-7) = 3, f'(3) = 10, g(3) = −7, and g'(3) = -9, find F'(3) =

A: Given, F(x)=f(g(x)),

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Q: Solve the initial value problem y¹6 = 0. y' = 1 + x x y15 (y(1) = 5 x > 0

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