Consider the following chemical reaction: Glucose + ATP → Glucose-6-Phosphate + ADP + Pi Given the following information, calculate the actual free energy change (G’) of this reaction. G’ of Glucose + ATP → Glucose-6-Phosphate + ADP + Pi = -16.7 kJ/mol [Glucose] = 5.0 mM [ATP] = 1.85 mM [Glucose-6-Phosphate] = 0.083 mM [ADP] = 0.14 mM [Pi] = 1.0 mM Temperature = 37 C R (Gas Constant) = 8.314 J/mol•K

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